So overall the mass will encounter a spring force stiffness equivalent to 4 times the stiffness of individual springs. This makes more sense.
Still I am unable to grasp the concept fully. But I will try.
Thanks for your help.
I think the forces on the right are increasing (mass pushes the springs).
Forces on left are decreasing (springs push the mass, as they are preloaded).
Considering x(t) [ displacement ] is positive to the right.
F_right spring 1 = - K x(t) [because it get compressed and pushes to left ]
F_right spring 2 = - K x(t) [because it get compressed and pushes to left ]
F_left spring 1 = K x(t) [because it gets released from preloaded position and...
Ok.
Well in my case the springs are preloaded to half of their allowable length. So. when the mass moves to the right (For example), the springs on the right will be compresses and push the mass to the left each with a force equal to -kx.
However, the springs at the left will now be released...
i think the two springs on each side are in parallel and the combined spring constant will be (K+K).
then the springs on both sides are in series to each other to the overall effect will be :
1/((1/(K+K))+(1/(K+K)))
Homework Statement
The mass is able to move in any direction. All springs are preloaded (compressed) to half their allowable loading capacity. Springs are not properly connected to the mass or ground (they are mounted on a rod on which the mass is moving). Ignoring all friction and gravity...
Hello all!
I am really stuck up here. I have made this circuit and want to measure the voltage across the capacitor. The voltage should gradually increase as the capacitor charges, and then become constant. But, I only get a constant voltage of 6V across the capacitor.
Infact, I have to...
Homework Statement
Given the first cycle of a waveform:
f(t)=2u(t)-2u(t-1)+u(t-2)-u(t-3)
-- Plot the first cycle of the wave form
-- Find the Fourier Coefficients
Homework Equations
Given above
The Attempt at a Solution
No idea yet. Will appreciate any help.
Similarity transformation results in a diagonal matrix. As you must know that diagonal matrices make calculations easier.
Similar matrices share a number of properties:-
They have the same rank
They have the same determinant
They have the same eigenvalues
They have the same...