Recent content by Hanga

This is not dircectly a coursework question, rather I need someone to tell me what is correct and what is not correct in my assumption of Momentum and collisions, esp conservation of linear momentum. For some reason I stand to believe there are two diffirent equations for conservation of...

NA should def be CW as it acts upwards from the floor. The cart must rotate CCW. Just as a fast moving car or motorcycle which accelerate fast enough would rotate CCW. So my final answer is that NA is CW and F and NB is CCW in this case. What would be the appropriate next step?

I'm not sure what you mean, I am afraid. I have no resource to study this, but i'll try. You want me to describe direction of torque from each force as cw, or ccw. NA would be CCW, as I stated its because it's below centre of mass. NB would be CCW. The force F is probably what I am having...

Ok so I checked so I believe it should be F+NA-NB as the force is below the centre of mass the cart want to rotate backwards. Doing this I get NA = 788,29 NB= 279,7, this is fairly close to the books answer but it's not correct. I'm not hunting for an answer tho, just the correct way of...

Not quite sure what you are getting at, but I can take either clockwise or counter clockwise as direction goes. Even if I take it counterclockwise it turns out wrong..

Homework Statement The total weight of the go-cart and driver is 1068N. The location of their combined center of mass is shown in attachment. The rear wheen exert a 106.7 N horizontal force together on the track. Neglect horizontal force on the front wheels. a) What is go carts...

Indeed you are freggin correct! I'm going to try this method on more example exercises 'till I fully understand it! Thank you, sir/mam!

Homework Statement The 8kg slender bar is released from rest in the horizontal position. When it has fallen 45 degrees, what are the x and y components of force exerted on the bar by the pin support A? Homework Equations F=ma where a= a t_hatt + v^2/p n_hat sin(45)=cos(45)=1/sqrt(2)...

Wow, you are so correct! I've just re-calculated everything and this time used my brain and, low and behold, I got alpha in the exact form I wanted. This without using nifty tricks, just accounting for all forces in all directions. I learned a great deal about friction and how to approach and...

Yes, that is true! I tried calculating it using M = F*R + 0.2*m*g*R as I assume friction is what it does, it hinders the attempted spin of the plate and creating a force helping my initial pull force. Though using this fact I get a much much higher angular acceleration of 46.42 rad/s^2. Even...

@ timthereaper Thank you very much, it helped a lot and I am on a good way of understanding this. I'm not quite there yet though :) @Doc Al Yes I do have an example! We have a cylindrical disc which lies on its side with a cord wrapped around it. You pull the cord with F tangentially...

Hey all! I'm currently doing some classical mechanics re-work and I've stumbled upon something that I don't quite understand. Calculating the angular velocity for, say a disc rolling on the ground, that has a tangential foce acting on it, I would view the angular acceleration from the middle...

The answer I am getting is like 0.004[insert a lot of numbers here] The answer it's supposed to be is 29degrees. The question is; How do I get the answer that I got 0.004(something) to degrees? You try it and we can see how you do it. The answer is supposed to be 29degrees.

Homework Statement We have the wavelength of 550nm and the distance (d) of 0.120mm. I need to calculate the the angle q. The diffirent parts of this questions corresponds to the diffirent order of n. a) Being n=1 b) n=5 c) n=10 Given variables; Wavelength = 550nm = 550*10^-9m d=0.120mm...