is this the correct answer for 'any row'
(c(76,41)/c(80,45))*5 - ( (c(76,41)/c(80,45))^5 + (c(76,41)/c(80,45))^4 + (c(76,41)/c(80,45))^3 + (c(76,41)/c(80,45))^2 )
so change of getting a row multiply by 5 = this will give me the chance of geting 1st OR 2nd OR 3th OR 4th OR 5th...