Recent content by HardestPart

I tried to solve the question ne more time as you told me,but am still getting a wrong answer mgH+1/2mv^2-s1umgcosa-s2umg=0 is the equation is correct?

Homework Statement When mass M is at the position shown, it is sliding down the inclined part of a slide at a speed of 2.07 m/s. The mass stops a distance S2 = 2.5 m along the level part of the slide. The distance S1 = 1.13 m and the angle q = 30.50°. Calculate the coefficient of kinetic...

I tried to fins the speed at angle 31 by: I/2mv^2+mg2R=1/2mv^2+mgRsina all m goes together v^2+4gR=v^2+2gRsina the answer i get from solving it i plugg into this: N+mgcosa=mv^2/R N=mv^2/Rsina-mgcosa I get N=18.27N but it is a wrong answer Can you tell me where i went wrong?

I tried to slove the question by : N+mgcosa=mv^2/r but i don't know what to put instead of N!?

I tried to find the speed of the mass at 31 degrees by: N+mgcosa=mv^2/r but i don't know what to but instead of N?

But I don't know which force I have to do to components I need cos ans sin right? How can I do that?

When I do the diagram the total forces work on the mass is : mg=mv^2/r the low of energy is: Mgh=1/2mv^2r But I can't see how the angle is related to the sloution?

Homework Statement A mass M of 6.00E-1 kg slides inside a hoop of radius R=1.40 m with negligible friction. When M is at the top, it has a speed of 5.23 m/s. Calculate the size of the force with which the M pushes on the hoop when M is at an angle of 31.0°. I have no idea from where to...

I know its incorrect-thats complicated- but I don't know what is the correct answer Do you mean after i get my answers for the equation I have to do SHIF COS A ->the solution i get and than i get my angle?

I solved the equation with the correct one: I get two answers 1-0.706 2--1.415 the first one is incorrect could it be the second one?can it be negative?

the equation is: l*g(1-cos^2a)=v^2cosa l*g*cos^2a+v^2cosa-l*g=0 that is befor i put in the numbers after: 1.51*9.8*cos^2a+3.24^2cosa-1.51*9.8=0 14.798cos^2a+10.4976cosa-14.798=0 that is the final equation did i make any mistake here?

I am doing my calculations over and over again but am getting the same answer ! I can't see where i was wrong!

Homework Statement A mass of 6.10 kg is suspended from a 1.51 m long string. It revolves in a horizontal circle as shown in the figure .http://capa2.cc.huji.ac.il/res/msu/physicslib/msuphysicslib/11_Force_Motion_Adv/graphics/prob03_pendulum.gif The tangential speed of the mass is 3.24 m/s...

http://capa2.cc.huji.ac.il/res/msu/physicslib/msuphysicslib/09_Force_and_Motion/graphics/prob07_twospring.gif

i tried to figure this question out: F=(l1+1.10)29.7 F=(l1+y+1.10)20.7 y=9 but its not correct any help?