Find the displacement of the springs

AI Thread Summary
The discussion focuses on calculating the displacement of two springs connected in a simple harmonic motion setup. The springs have constants k1=29.7 N/m and k2=20.7 N/m, and they are stretched by a force F after being displaced by 1.10 m. The user attempts to apply Hooke's Law but encounters difficulties in solving for the displacement y. They express confusion over the relationship between the forces acting on each spring and seek hints for the correct approach. Clarification on the application of Hooke's Law and the relationship between the displacements of the springs is needed to resolve the problem.
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A question:Simple harmonic motion

http://capa2.cc.huji.ac.il/res/msu/physicslib/msuphysicslib/09_Force_and_Motion/graphics/prob07_twospring.gif1.[/URL] Homework Statement
Two springs with spring constants k1=29.7 N/m and k2=20.7 N/m are connected as shown in the figure:
Find the displacement, y, of the connection point from its initial equilibrium position when the two springs are stretched a distance d = 1.10 m as a result of the application of the force F

http://capa2.cc.huji.ac.il/res/msu/physicslib/msuphysicslib/09_Force_and_Motion/graphics/prob07_twospring


Homework Equations


Hooks law: F=Kx



The Attempt at a Solution


since the same the same force streches each spring :
k1.x=k2.x
FROM HERE I STUCKED
ANY HINT?
 
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i tried to figure this question out:
F=(l1+1.10)29.7
F=(l1+y+1.10)20.7
y=9
but its not correct
any help?
 
Two springs with spring constants k1=29.7 N/m and k2=20.7 N/m are connected as shown in the figure:
What figure?
 
http://capa2.cc.huji.ac.il/res/msu/physicslib/msuphysicslib/09_Force_and_Motion/graphics/prob07_twospring.gif
 
Last edited by a moderator:

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