So i know the total time is 8.6 s
t1 + t2 = 8.6s
And from the (v^2 - v0^2 = 2as) i will get that after 15m the velocity which is also the highest velocity
v^2 = 30a
And then after that the velocity will be constant (s = v*t)
45/t2
Now i am stuck here because i have 3 equations but 4...
Thank your for your reply but i don't really understand yet
Are you saying that when the force F1x is increased the wire will eventually break?
And F1 will always stay the same right? its just the F1y and F1x that will change?
First i calculated the sign Force which was 4*9.81 = 39.24N
which meant that the force already exceeds the traction force.
What i don t understand in the question is how the distance h will avoid this?
Well i learned about torque and to achieve equilibrium it has to be the same on the left of the torque point and to the right.
My problem with this question is i don't know how to deal with
I know what to do on the right.
Torque RIGHT = 500 * F
but the rest i am confused about