Recent content by harihrn

I've been studying rotational motion for a while and I have no clue how moment of inertia plays a role in it. How would you define it? Often times, it's just described as resistance to change. Does that mean a high moment of inertia means a higher resistance to change or is it the other way...

but the momentum isn't transferred to the ramp itself is it? the ramp doesn't move at all

yeah it's part of the problem, probably a distraction. it's right before the rope starts to stretch. and also, it is to be assumed that the guy survives the fall

A bungee jumping gig is about to be performed off a bridge at a height of 100ft. The length of the rope is 20ft. The K constant for the rope is 200n/m and the air resistance is 12N(only vertical). The jumper's mass is 100kg. When the man jumps, the rope snaps right before it starts to stretch...

thank you so much!

but as per what you said before, when falling, the KE+grav.pe should be equal to the elastic potential energy, the method should be SUM of Energies during fall = 83.5x^2+12x+mgx (x being the amount stretched) or SUM of Energies during fall -mgx= 83.5x^2+12x(x being the amount stretched) . they...

thank you very much! but as per what you said, if i account for the energy gained from falling after the rope begins to stretch, i get the same answer i get for my 3rd attempt, which is 4.4 m stretch. SUM of Energies during fall = 83.5x^2+12x+mgx (x being the amount stretched) if u mean that...

this problem involves a man jumping off a bridge with a bungee chord holding him. he weighs 102 kg and the stretch constant of the chord is 167n/m. And there is a 12N air resistance. the length of the rope when slack is 20 ft what is the minimum height needed for him to do this? my attempt: i...

so what would be the conceptual formula that i should use? like which method of the ones that i did is right?

i really need some help

there is another way i did it and it gave me ANOTHER answer, lol i must sound annoying, but i watched a simulation which showed that when the chord is fully stretched, the kinetic energy during the fall converts to elastic potential and gravitational potential. so, i set the KE = mgx+0.5kx^2, x...

my bad I'm new to this lol

Im not sure whether my approach was right in the first place, since another method that i tried gave me a different answer. I set mg(height of the bridge)= 0.5kx=(height-the length of chord/rope)^2 which gave me 22.3 m.

yes of course, i divided the problem into three parts, the initial fall till the rope starts to stretch, then the stretch the Ke value that i came up with was mgH, and the sum of the energies is KE-W, which was mg(6.09) -12(6.09). 6.09 m is the length of the chord when it is slack (20ft). the...

Um this problem involves a man jumping off a bridge with a bungee chord holding him. he weighs 102 kg and the stretch constant of the chord is 167n/m. And there is a 12N air resistance. what is the minimum height needed for him to do this? thanks! (one more thing, the length of the rope when...