A bungee jumping gig is about to be performed off a bridge at a height of 100ft. The length of the rope is 20ft. The K constant for the rope is 200n/m and the air resistance is 12N(only vertical). The jumper's mass is 100kg. When the man jumps, the rope snaps right before it starts to stretch, making him land on a scooter on top of a ramp. If the ramp is elevated 5 degrees, and the length of his path down the ramp is 50 ft, how fast will he be going as he runs down the ramp on to the surface of earth? (assume 0 mass for scooter and no friction on ramp) I attempted the problem thinking that the KE from the fall would convert into the KE during the run on the ramp. so i did Ke+Fe(15.24) = 1/2mv^2; with fe being sin(5degrees)m*g Ke = mg(total height-height of ramp) - 12(total height-height of ramp); 12 being the force of friction. i got 24.3 m/s as the answer. But when this was attempted on a simulator, it showed a rise in thermal energy, which is essentially work i did not account for. So how would i exactly approach this problem?