Recent content by Harikesh_33

How do I interpret physically what dipole moment is ? The explanations that I received were "two charges seperated by a small distance " ,"it talks about ability of a dipole to rotate under the influence of an Electric Field " ,"Second term of the Multipole expansion" ,I get that these terms...

***A Carnot Engine*** is a theoretical engine unlike a Sterling Engine which can be made practically. Some of the drawbacks of Carnot Engine are, 1)The Heat Transfer occurs only during isothermal process(compression and expansion),this is because the working material (ie) gas or fuel used, if...

Aren't we considering the charges placed on the centre and vertices of the cube ? And are you coming to the conclusion that it's a saddle point because both the first and second derivative is zero (follows Laplace's equation )

Sorry for framing the question like that ,to provide some context ,if I am not mistaken ,Laplace's equation is being used to prove Earnshaw's theroem ,But how can we use Laplace's equation here ? Change density is non zero here .

I have a follow up question if you don't mind ,why is earnshaws theroem not true ? I understand that it has something to do with the fact that it's an unstable equilibrium(or it is said so and I don't understand why it is said so ) and potential is maximum for an unstable equilibrium and this isn't

Yeah but won't the properties of the harmonic function vanish if we use Poisson's equation ?

Let me get this straight ,so Laplace's equation is used to find a potential function ,now if the potential obeys Laplace's equation then we can find the average potential around a sphere just by taking the potential at the centre of the sphere ,now here comes the catch ,Laplace's equation...

Why doesn't the **Laplace's equation**(#\nabla^2V=0#) hold in the region within the sphere when there is a charge inside it ? Is it because #ρ \ne 0# within the sphere and it becomes a **poisson equation**($\nabla^2V=\dfrac{-ρ}{ε_0}$) and changes the characteristics of **Harmonic Solution**...

The first law of Thermodynamics states that the change in Internal energy is equal to the sum of Heat gained or lost by the system and work done by the system or on the system . $dE=Q-W$...(1). In an Adiabatic process ,Q=0 . Therefore $dE=-W$ . Now...

You can try Quantum Theory by David Bohm

Correct me if I am wrong ,but the constant Torque is provided by the Kinetic Friction here . Doesn't a lower centre of mass make it even harder to get out of the mud ? (Lower Centre of Mass -an object becomes more stable ) . Isn't the job of Kinetic Friction to attain Rolling without Slipping ?

1)When a wheel is stuck in mud it rolls with slipping ,this means that at the point of contact it has a net velocity As we can see from the image Kinetic Friction acts in the direction opposite to the resultant velocity ,this effectively reduces the tangential velocity at the surface and tries...

The vector from point through which the rod is rotating to the mass . I have drawn r Vector in second image .

Question regarding finding the magnitude of Torque of a system of two masses attached to a rod rotating at angle of θ degrees with respect to a vertical

So flux itself doesn't have a very good meaning ? It's only purpose is to find Electric Field ,but why is the flux equal to 4πQ intuitively(Gaussian units) lime you mentioned before ?