Recent content by heavyarms

Thanks! Your help is very much appreciated. BTW, Merry Christmas! :biggrin:

Thank you for your suggestion. I've just tried it on my TI-83 Plus SE and it gave me.. [[1 0 0 3] [0 1 0 -1] [0 0 1 4]] I know that is the correct answer, but the textbook requires me to show all the steps. The problem is I am stuck midway to obtaining the answer. (See the first post...

The full question is as follows: Solve the following system by the Gauss-Jordan elimination method. 2x + 5Y - Z = -3 X - Y + 4Z = 20 3X + 2Y - Z = 3 Indicate the row operation used in each step.

So as long as I obtain an answer, it is still correct no matter the method I use? If this is the case then my textbook is really odd... it states that (1,1) has to be either +/- 1 and that multiplication changes can only occur in one row when adding.

Do I not have to isolate a 1 in the top left hand corner? i.e. [ 1 X X | X ] for the top row? Also isn't it not allowed to changed two rows at a time?

Gauss-Jordan Elimination Method Help! Hi, I'm having a problem solving the following using the Gauss-Jordan Elimination Method. I am wondering if someone can help me... i.e. [ [2 5 -1 -3] [1 -1 4 20] [3 2 -1 3]] I've tried solving it by... R1<-->R2, R2+(-1)R1, R3+(-3)R1...

help please: sequence problem how do you solve this question please help! thx! A current population is 2 000 000 and it increases 7% annualy. However each year a certain number of people die (this amount is constant for every year). How many people die each year if the population is to...

The derivative of e is 0 since e by itself is a constant (just like pi). The derivative of e^(1+x) is [e^(1+x)][1][dx]. The derivative of e^x is (e^x)(dx) Hope that clarifies things up for you.

yes, but i sort of used pythagerus to solve them, not vectors... A, B, C i can do fine... but D, E, F bit sketchy... :confused: So any help would be appreciated... Thanks!

Please help with problems please! All questions need to be solved using vectors. See enclosure for questions :biggrin: Thank you! Or go to: http://img128.exs.cx/img128/9089/questions2.jpg