Recent content by HeheZz

This is my question: E1 = there is no rain E2 = concrete material production is feasible E3 = premix concrete is available On a day given, casting concrete depend on the availability of material. The required material may be produced and send to the site from premix concrete supplier. However...

OK! I got it! Tnx for the help very much! I didnt realize this mistake and was really stress over it.. Thanks again for the help and I got the answer :D

ok so its ∫(0-2)∫(0-2pi) (∇xF).Nr dθdr Therefore its: ∫(0-2)∫(0-2pi) -xz-x^2-z-3 dA (Using x = rcos(θ), y = rsin(θ), z = 0.5r^2) = ∫(0-2)∫[(0-2pi) -0.5r^3cosθ - r^2cos^2(θ) - 0.5r^2 - 3]r dθdr Im not sure is my steps correct? Jus a little problem with integrating cos^2(θ)...

Do you mean the range values when i am integrating? I don't understand what to use. Isnt it 0-pi for the inner integral and 0-2pi for the outer integral?

N is the normal vector? where r(θ,φ) = (3sinθcosφ, 3sinθsinφ, 3cosθ) and N = rθ X rφ Thus, N=9sin^2(θ)cos(φ)i+9sin^2(θ)cos(φ)j+9cos(θ)sin(θ)k

Homework Statement Verify Stokes Theorem ∬(∇xF).N dA where surface S is the paraboloid z = 0.5(x^2 + y^2) bound by the plane z=2, Cis its boundary, and the vector field F = 3yi - xzj + yzk. The Attempt at a Solution I had found (∇xF) = (z+x)i + (-z-3)k r = [u, v, 0.5(u^2 + v^2)]...

Homework Statement Verify Gauss Divergence Theorem ∭∇.F dxdydz=∬F. (N)dA Where the closed surface S is the sphere x^2+y^2+z^2=9 and the vector field F = xz^2i+x^2yj+y^2zk The Attempt at a Solution I have tried to solve the left hand side which appear to be (972*pi)/5 However, I...

Tea, i try using polar coordinates.. In the spherical, the equation of the sphere is r = 1 And the cone is rcosθ=√(r^2 sin^2 θ cos^2 φ + r^2 sin^2 θ sin^2 φ)=rsinθ If we divide both sides by rcosθ, then we get tanθ=1,θ=π/4 So, we have the triple integral: ∫0-2pi ∫0-(π/4) ∫0-1...

Homework Statement Find the volume of a region bounded above by the unit sphere x^2+y^2+z^2=1 and below by the cone z=sqrt(x^2+y^2). I am really confuse here.. >< Homework Equations Sphere: x^2+y^2+z^2=1 Cone: z=sqrt(x^2+y^2) The Attempt at a Solution I had plot the graph of the...

o.. sry >< new to this forum

Can someone help? Find the volume of a region bounded above by the unit sphere x^2+y^2+z^2=1 and below by the cone z=sqrt(x^2+y^2). I am really confuse here.. ><