Recent content by HelloMrCo

Hey thanks for helping me! I was having a really hard time solving this problem.

So I'll still be using the same formula that was given to me when solving for a regular spillover but with the addition of the steel sphere. So the equation will be: Spillover = Delta V(Mercury) + Delta V(Steel) - Delta V(Container) Is this right?

So that means I have to subtract the volume of the steel sphere to the volume of the brass sphere in order to get the volume of the mercury. But still I have the problem on how to get the spillover because it is a whole different equation since the container is spherical.

It is stated in the problem that the sphere brass was filled with mercury so that means it is the same volume.

Side note: I'm using the equations that our professor gave us about thermal expansion and the equation for a regular spillover is: Spillover = Delta V(Liquid) - Delta V(Container) I also don't have an idea how to solve for the spillover with another material inside the container.

So what would be the equation now if that is the case?

Homework Statement A spherical brass shell has an interior volume of 1.60 x 10-3m^3. Within this interior volume is a solid steel ball that has a volume of 0.70 x 10-3m^3. The space between the steel ball and the inner surface of the brass shell is filled completely with mercury. A small hole...