Recent content by heterotic_

Realistically, that is only a good conclusion when you discuss the outcomes the two produce independent of each other. However, we are discussing bridging the gap, so saying not to, is just illogical. If we think about what a wave really is, we envision that oscillating line we produce with...

Redundancy would be silly, so I brought it back. I would say that we cannot calculate the "classical" radius of a photon like an electron, because a photon always moves at the speed of light. But what about calculating the mass of a photon depending on its energy? I know people say the photon...

The actual radius of an electron is calculable, it is just dependent on its environment, so shouldn't this be also true of a photon? Everything has a center, even if it is so small, its entire volume is its center. It is how far it is spread out that is changeable (or rather, how concentrated...

I'm bringing this conversation back from the dead, because I feel like it has some sort of meaning. If we talk about size in a non-conventional sense of the word, but as the average minimum amount of space it occupies, doesn't everything have to have a size? If two variables "try to" occupy the...

You can determine instantaneous velocity at each point, because at any instant in time, velocity will be constant. Since acceleration is the rate of change in velocity, given the instantaneous velocities and time of change, that gives you an accurate acceleration, as I already proved above.

I'm getting dual degrees in atmospheric science and astronomy right now. Your first reply said that "you cannot use v = d/t". Doesn't your equation also assume it is a vacuum? If we assume there is an atmosphere, we'd have to use another Method, right? Aren't we also assuming that there also...

Sorry about the mistaken calculation above. I was multitasking doing my own physics homework, then got logged and had retype everything and mistakenly multiplied instead of dividing. Anyway, I wasn't asking if I was right or wrong. Why do people say "I'm afraid" when pointing out an error? Are...

d = 1/2(at^2) and d + 2.3360 = 1/2(a(t+0.1)^2) and d + 2.3360 + 2.4000 = 1/2(a(t+0.2)^2) right? 2.336 = 1/2(a(t+0.1)^2) - 1/2(at^2) 2.336 = 0.1a(t+0.05) a = (t + 0.05)/.2336 and 4.736 = 1/2(a(t+0.2)^2) - 1/2(at^2) 4.736 = 0.2a(t+0.1) a = (t + 0.1)/.9472 so (t + 0.05)/.2336 = (t +...

We had a similar problem in class and this was the solution we used to solve it, we assumed there was no drag due to an atmosphere. The initial velocity IS known. The problem states the rock is dropped from a rest (initial velocity of 0), the unknowns are the initial height, the time in transit...

If there are 10 flashes per 1 second, in perfect intervals, each of the 5 remaining images are 1/10th of a second apart, making the change in time for each image of the rock .1 seconds. If the change in distances are 2.3360 m, 2.4000 m, 2.4640 m and 2.5280 m, and v = d/t, then we have...

Can't we estimate it, though? In a physics course I am taking, we had to prove why or why not skydiving on the moon from 4 km would kill you. The only way to prove this, short of real experimentation, is to figure out if the net force of the impact exceeds current demonstrated levels of force...