hmparticle9's latest activity
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Hhmparticle9 posted the thread Calculating <r> from <x> with no further calculation in Advanced Physics Homework Help.This is part of a larger, more difficult question. But this is the part I was a bit stuck with. ##\langle r \rangle = \frac{3}{2}a## and...
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Hhmparticle9 replied to the thread Quantum mechanics book recommendations.@vela I guessed that was the case.
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HIs Griffiths your first exposure to quantum mechanics? If so, you might consider working through the chapters on modern physics in an...
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Hhmparticle9 reacted to bob012345's post in the thread Quantum mechanics book recommendations with
Like.
I have seen Quantum Mechanics: The Theoretical Minimum by Leonard Susskind and Art Friedman recommended as it is less math oriented. -
HI am currently reading through "Introduction to Quantum Mechanics" by Griffiths and I am loving it. I am interested in book about...
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Hhmparticle9 replied to the thread Need help understanding this figure on energy levels.I think I get it. For instance if ##n=2##, then from ##n = N + l## we have either ##N = 2, l = 0## or ##N = 1, l = 1##. These match the...
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Hhmparticle9 replied to the thread Need help understanding this figure on energy levels.@kuruman Let us first look at the first image and your post #2. Your explanation makes perfect sense :) Thank you again for your help...
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Hhmparticle9 posted the thread Need help understanding this figure on energy levels in Advanced Physics Homework Help.This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I...
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Hhmparticle9 replied to the thread I Derive the orthonormality condition for Legendre polynomials.I see :) I was just keeping the leading term. When I think about it I was being a bit reckless. I appreciate your initial solution, very...
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Hhmparticle9 replied to the thread I Derive the orthonormality condition for Legendre polynomials.Thanks :) I try my best not to give in, but sometimes... I am sure that ##D^{2m}[(x^2-1)^m] = D^{2m-1}[m(x^2-1)^{m-1}2x] ## ???
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Hhmparticle9 reacted to fresh_42's post in the thread I Derive the orthonormality condition for Legendre polynomials with Like.
I have ##(2m)!## Let's see. We only need to consider the highest term of ##(x^2-1)^m## at each differentiation. So we have to solve...
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Hhmparticle9 replied to the thread I Derive the orthonormality condition for Legendre polynomials.You are correct. I am wrong. I just peeked at the solution. This problem has given me a major headache. Can you see where I got the...
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Hhmparticle9 replied to the thread I Derive the orthonormality condition for Legendre polynomials.Okay. I said $$D^{2m}[(x^2-1)^m]$$ $$=D^{2m-1} [m(x^2-1)^{m-1}2x]$$ $$=D^{2m-2} [m(m-1)(x^2-1)^{m-2}2^2x^2 + 2m(x^2-1)^{m-1}]$$...
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Hhmparticle9 replied to the thread I Derive the orthonormality condition for Legendre polynomials.Okay, so I have ##D^{2m}(x^2-1)^m = 2^m(m!)^2##. I am having more trouble with the integral.
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Hhmparticle9 replied to the thread I Derive the orthonormality condition for Legendre polynomials.Thanks. I follow your logic till I obtain: $$||P_m||^2 = (-1)^m \frac{1}{(2^m m!)^2} \int_{-1}^1(x^2-1)^m D^{2m} (x^2-1)^m dx$$ I am...
