Recent content by Hobbit300

  1. H

    Spring with masses on either side - force constant and compression remain the same?

    Homework Statement A spring is compressed by 0.100m from its equilibrium position, and two blocks of masses 3kg and 5kg are resting motionless on each side on a frictionless surface. The spring has a force constant of 20 N/m, and a rope holds the block in position against the compressed...
  2. H

    Application: using energy and momentum to calculate estimated weight

    I was using 9.8 because m2 is only the mass of the polar bear. For weight, which equals mg i would have to multiply by 9.8, or so i thought? If they meet they would collide.. but i don't understand how i could take velocity out of the equation since their final velocities would not be equal...
  3. H

    Application: using energy and momentum to calculate estimated weight

    ...so he would slide forward while pulling the bear closer! Thank you! I think I've got it now, but would you check if I'm on the right track? so i know that v1i and v2i =0, but v1f and v2f are not. I'm thinking their velocities would not be equal because their masses are different... so i end...
  4. H

    Application: using energy and momentum to calculate estimated weight

    If the hunter was sitting down then his initial and final velocity would both be zero - this leaves me with m2v2i=m2v2f. if the polar bear starts with inital 0m/s or any other velocity i still end up with m2v2i = m2v2f. if v2i=0, 0=m2v2f, and whatever v2f equals, m2=0. if v2i=2m/s for example...
  5. H

    Application: using energy and momentum to calculate estimated weight

    Homework Statement An arctic hunter goes hunting polar bears and shoots one. He finds it lying dead on a large patch of almost frictionless ice. He has no scales or weighing device of any kind (and of course, there's nothing to hang it on) but he does have a long rope. How can he get a pretty...
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