Recent content by hodeez

thanks himanshu, but i seem to have got it in school, before i got a chance to see your answer. Even so, the problem was logically incorrect ( f'(4) was suppose to be f'(3)). I should be 85+ for my finals. thanks.

Can't seem to solve Long problems #1. All I got was a) which is K=9(?) to make it continuous. But to use the H method for B got me all confused!

No worries, I usually achieve 90+ marks and the first one to leave the classroom/finish the test. I hate checking =_=

ugh, i think i understand the concept, so let's recede back to the short answers! :wink:

OH NO! the 2!

hope i got this

I see my error, I forgot to square the C and derive it, so then I would have to divide the right side by C... Gotta run to the store for my co-workers, so I'll be right back to figure that out :smile:

My formula is C= A^2+B^2-cos(c)*A*B Is that the correct form? But 2.344 seems too way out of proportional

The method, I'm sure is correct, because that is the method we were taught to use. But my mechanics are probably incorrect. I'm using the Google calculator as I don't have my graphing calculator right now.

wow, that would have caused havok on the final

is the answer 56.52 rounded? I used the Cosine Formula for triangles. Also, I am interested in hearing your relative velocity concept. =)

y'= 3(sin(x))(cos(x)) y''= 3 * product rule (sin(x))(cos(x)) = 3 * (sin(x))*(-sin(x))+(cos(x))(cos(x)) = -3(sin^2(x))*(cos^2(x))

May you check this (#9): y'' = -3(sin^2(x))*(cos^2(x)) and then plug in pi/6 = 180/6 = 30, yes?

im quite consfused on the way you are approaching it. I am thinking, if its continuous the 1st piece must match the 2nd piece @ 3 and then i set it up for k/3+2=k-3-1 and then solved for k which = -9 , then the slope must equal so I am finding the deriv of both pieces and then trying to make...

DOH! another simple one over looked