Recent content by Hollysmoke

Hi, I was wondering if someone could help explain how the following shapes would affect convection. What it is is a heat plate with nothing, a bundle of tubes, and just fins. It's in a vertical tube and the air flows upwards. I understand convection but I don't get how it would be affected in...

Homework Statement The following reaction initially contains [A]o = 0.2150 M and [B]o = [C]o = 0.4150 M. If the equilibrium constant for the reaction is Keq = 2.03, what are the concentrations of reactants and products when the reaction has achieved equilibrium? What is the value of deltaG for...

Homework Statement A sealed 1.00 L vessel contains 0.3475 g of argon gas and 6.766 g of an unknown gas at 350 K. If the total pressure of the gas mixture is 2.56 atm, and the unknown gas has an empirical formula of CH2, what is the molecular formula of the unknown gas? Homework Equations I...

1. Consider a rectangular water tank with a length of 8m, a width of 4m , and a height of 5m. Water exits the tank by pouring over the sides. a) If the tank is initially full of water, find the work required to empty the tank. b) If the tank is initially half-full of water, find the work...

I figured out the 2nd one ^^ Just need help with the differentiation one.

I just have two questions: A fundamental problem in crystallography is the determination of the packing fraction of a crystal lattice, which is the fraction of space occupied by the atoms in the lattice, assuming that the atoms are hard spheres. When the lattice contains exactly two...

oh okay. Thanks.

How can I calculate cos ^2 (53)?

It should be e / 1, since the limit is approaching -2, then -1 < x+2 < 1, or x+2 < 1, so delta = 1 and e / 1 ?

Then it'd be delta = e / 0

since it's a value close to -2, can we assume that it is within a distance 1 from -2, that is, -1<x+2<1 , -3 < x < -1 Here's where I was confused: Do I add 1 since the other value was x + 1? so, I'd be -2 < x + 1 < 0 ?or x + 1 < 0 ?

We need to find such a number that restricts x to lie in some interval centered at 2, right?

I get delta = min {1, e/0}

I thought that was enough...where did I go wrong?

I'm supposed to prove that lim x -> -2, x^2+3x+7 = 5 Here's what I have: |x^2 +3x+7 – 5| < ε |x+2| < δ |x^2+3x+2| -> |(x+2)(x+1)| < ε whenever |x+2| < δ |x+1||x+2| < δ |x+1| |x+1||x+2| < δ|x+1| < ε ε / |x+1| > δ , as x -> -2, |x+1| -> 3, therefore: ε / -1 > δ But...