Recent content by hovercraft57

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    Centrifugal Force load caused from propeller rotation

    the section of the blade is the same 4 inches from the centre to the tip. The lbs/inch is .1111/1 inch of the aluminum flat bar used for a blade. there are 2 blades. I thought not using the weight /inch of the clark -y section would give a ssafety margin. Thanks ED
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    Centrifugal Force load caused from propeller rotation

    Is anyone interested in telling me the force created from 2 propeller blades rotating 2000 rpm.The total diameter of the prop is 72 inches and the weight of 1 blade is 4 lbs. Reason for the question is I want to mill a clark-y profile the length of the blade less ,4 inches for a bolted...
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    Bolt hole fit and effect on shear capacity

    If I use the un-threaded section of a 3/8th inch bolt as a pin to lock a sprocket hub to a drive shaft I would drill and ream so that the bolt would need to be lightly tapped to go through the assembly. If the fit was looser (.025 thousands clearance) would that reduce the capacity of the...
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    What Size Bolt Do I Need for 10,000 ft/lbs of Torque on a 1.25 inch Drive Axle?

    Thank You Jack Action for your valuable input. So given the wheel is driven with a 525ft/lb torque I need to select a grade 8 bolt to use as a pin through the drive sprocket hub and 1.25 dia drive axle. Would a 3/8th dia.grade 8 bolt be ok if the unthreaded shank part of the bolt is on the...
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    What Size Bolt Do I Need for 10,000 ft/lbs of Torque on a 1.25 inch Drive Axle?

    No it doesn't need to go fast. I am using it to pull a boat on rough narrow trails around Hearst Ontario Canada. Last thing I need is a collision with a tree when months could go by before seeing another person. About 10 miles per hour is max.The drive train is like an Argo ATV which has a skid...
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    What Size Bolt Do I Need for 10,000 ft/lbs of Torque on a 1.25 inch Drive Axle?

    Thanks SteamKing for your response I have been thinking about the problem for a time now and concluded the scenario is unlikely. This contraption I want to build have 6 wheels driven on 6 separate axles (3 on one side and 3 on the other side) so it is a skid steer arrangement. Would the drive...
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    What Size Bolt Do I Need for 10,000 ft/lbs of Torque on a 1.25 inch Drive Axle?

    20hp@3000rpm=35ft/lbs 20hp@10rpm=10,000 ft/lbs using the formula hp x 5252 divided by rpm of shaft Can that be right
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    What Size Bolt Do I Need for 10,000 ft/lbs of Torque on a 1.25 inch Drive Axle?

    If a gas engine makes 20 hp at 3000 rpm I figure the ft/lbs of torque equals about 460. Negating friction if the drive axle the engine turns goes 10 rpm with 20 hp the ft/lbs of torque equals about 10,000. I was using the formula hp x 5252 divided by rpm of shaft What I need to know...
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