Recent content by HPt

Hi autoUFC, you have to distinguish quantum states, microstates and macrostates: Quantum states are represented by vectors in the state space and they can be superpositioned. If ##\binom 1 0## and ##\binom 0 1## represent quantum states then also does their superposition...

To better understand the thermodynamic cycle you described, could you maybe shortly explain (or provide a link to) what primers and carriers are and how they work in the context of your proposed experiment?

Exactly. However, if you calculate the entropy change with statistical mechanics in the conventional way (see most textbooks, such as Huang, or section 2 of my paper) you do get a non-zero entropy change. This is the "false increase in entropy" I'm referring to in the abstract of my paper.

I believe your misconception is that you think of putting one kind of gas of distinguishable particles in one part and another kind of gas of distinguishable particles in the other part (such that you have knowledge of what particle is in which part). But that's not the setup. Instead think of...

For large particle numbers, the entropy contribution that stems from the uncertainty about how many particles are located in each subsystem is negligible. For that reason, it isn't of relevance in the present context of the Gibbs paradox. Nevertheless, as an aside, this uncertainty is...

A paradox, as I understand it, is a seeming contradiction between two statements that are both believed to be true. In section 2 of my paper I frame the Gibbs paradox in such a way that it reveals a contradiction between the conventional entropy calculation and the second law. I resolve this...

No, QT is not needed. In section 4 of my paper I show that there is no entropy increase when mixing distinguishable identical classical particles.

No, that's only the case if you know which particle is in which partial volume. Consider the following simple thought experiment: Take a volume, then put 1,000,000 different buckyballs in it, and now divide this volume into two equal halfs. After that you have two partial volumes, each...

Pairwise different means that you can choose any two of them (i.e., any pair) and they are always different.

You can make a gas out of pairwise different buckyballs and show that this gas (although treated strictly quantum-mechanically) suffers from the Gibbs Paradox just like a gas of classical distinguishable particles. I invite you to read my paper where I do exactly this.

Hi, I'm the author of the paper Eur. J. Phys. 35 (2014) 015023 (also freely available at arXiv). As I explicity demonstrate in my paper, there is a paradox that manifests as a contradiction to the second law of thermodynamics. This contradiction does not only arise for classical distinguishable...

@ Andy Resnick: Your PDF and the references therein do not contain maline's (correct) solution. @ maline: Your solution is correct. I published this solution 2010 in Journal of Statistical Physics http://www.springerlink.com/openurl.asp?genre=article&id=doi:10.1007/s10955-010-0077-7 and, more...

@fxdung: DrDu is right. In Eur. J. Phys. 35 (2014) 015023 http://dx.doi.org/10.1088/0143-0807/35/1/015023 (also available as arXiv preprint) you will find a detailed demonstration of the Gibbs paradox (in the form of a violation of the second law of thermodynamics) along with its resolution...

In Eur. J. Phys. 35 (2014) 015023 http://dx.doi.org/10.1088/0143-0807/35/1/015023 (also available as arXiv preprint) you will find the resolution of the Gibbs paradox for distinguishable particles (classical or not).