Recent content by hs764

1. One gram of water occupies a volume of 1 cm3 at atmospheric pressure. When this amount of water is boiled, it becomes 1671 cm3 of steam. Calculate the change in internal energy for this vaporization process. The heat of vaporization for water is 2.26 x 106 J/kg. 2. w = -PΔV, E = q + w...

So ΔL/L = 4.0 x 10-4?

Oh, right...F/A would be 135 N / 5.0 x 10-6 m2 = 2.7 x 107 N/m2?

Homework Statement Just wanted to check my work on this one. An aluminum wire is clamped at each end under zero tension at room temperature. The tension in the wire is increased by reducing the temperature which results in a decrease in the wire's equilibrium length. What strain (ΔL/L) will...

Great, thank you!

So using conservation of momentum I got the same thing...dA/dt = L/2m = mr2ω/2m. Given that ω = v/r, rpvp/2 = rava/2, va = rpvp/ra.

1. Asking because the answer I got seems too simple...a planet of mass m moves in an elliptical orbit about the sun. The minimum and maximum distances of the planet from the sun are called the perihelion and aphelion respectively. If the speed of the planet at p is vp, what is its speed at a...

Yeah, I did your calculation and still got x = 1.76 m.

Awesome, thank you!

Ahhhh okay I was thinking about the axis incorrectly. So the total torque produced by the tension in the rope would be (50 N)*(cos 37)*(3.01 m) + (50 N)*(sin 37)*(3.99 m). Alternatively, I could just use (50 N)*(5 m)*(sin 74), right? And then solving for x gives x = 1.76 m?

Right, because it's the horizontal component of the tension that produces torque here. So this way I got τtension = (50)*sin(53)*3.01 m, which gave me x = 0.26 m.

I just calculated the torque for the rope, the rod, and the block. For the ropeI got τ = 50*sin(37)*5*cos(37), for the rod I got τ = 50*(5*cos(37)/2), and for the block I got τ = 100*cos(37)*x. Then I just plugged that into τrope - τrod - τblock = 0. I think I was slightly off the first time...

Homework Statement A uniform rod AB of length 5 m and weight 50 N is pivoted at A and held in equilibrium by a rope as shown. A load of 100 N hangs from the rod at a distance x from A. If the breaking strength of the rope is 50 N, find the maximum value of X. Homework Equations τnet =...

Right - thank you!

So, α = [((m2g-m1g)Lsin(90 - θ))/2] / [(M/12 + (m1 + m2)/4)L2]? Was my calculation of the inertia correct?