Recent content by Hurricane939

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    Why doesn't a fluorescent lamp implode and shatter ?

    So if the lamp shape was rectangular for example, would it shatter ?
  2. H

    Why doesn't a fluorescent lamp implode and shatter ?

    Accoring to Wikipedia, the pressure inside a fluorescent lamp is 0.3% of the atmospheric pressure, so the pressure difference between the outside and the inside of the lamp is almost equal to the atmospheric pressure which is 1 bar or 14.7 psi. Now according to this and this, glass shatters at...
  3. H

    Will this rope break due to the tidal forces or not?

    So in this situation, we don't need to look at the tidal gravity over the length of the 200 km chunk, but rather on the tidal gravity between this chunk (its center of mass) and the center of the Earth since it is still attached to the Earth. right ?
  4. H

    Will this rope break due to the tidal forces or not?

    So it's the tidal gravity difference between the 200 km chunk and the center of the Earth that will cause the breaking. Is that correct ?
  5. H

    Will this rope break due to the tidal forces or not?

    Now we are back to the same point that is confusing me. Which tidal gravity difference is causing the breaking, between the surface and center or over the length of the rock column ? Also, how large will the chunk be in our new case ?
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    Will this rope break due to the tidal forces or not?

    Will this increase be so significant that our used order of magnitude estimation will be meaningless or it is not that significant ?
  7. H

    Will this rope break due to the tidal forces or not?

    There is one last question that came to my mind while thinking about this. As you can see, we found that a chunk of 7.5 km should be ripped from the Earth if the tidal gravity between the core and surface is 10.5 m/s2. Now, by using the conditions that lead to this tidal gravity, I calculated...
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    Will this rope break due to the tidal forces or not?

    I am sorry, it seems I have made a mistake calculating the breaking length. In case of tidal gravity between core and surface of 10.5 m/s2, the breaking length is 7.5 km rather than 75 km.
  9. H

    Will this rope break due to the tidal forces or not?

    Yea I am by no means trying to get accurate results. I am just try to get a general idea of how large there chunks can be. Thank you very much for explaining all this.
  10. H

    Will this rope break due to the tidal forces or not?

    That's perfect. Let me summarize what I understood and please correct me if there is something wrong. If, for example, the acceleration of the surface due to the black hole is 20.5 m/s2 and the acceleration of the center due to the black hole is 10 m/s2, then the tidal gravity between core and...
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    Will this rope break due to the tidal forces or not?

    Ok great. This is actually why I asked this question, but there is still one thing that confuses me. First of all, let's keep the Earth gravitational acceleration at 10 m/s2 as you said. The thing that confuses me is what "g" I should use in the breaking length. For example, if we have tidal...
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    Will this rope break due to the tidal forces or not?

    In page 33 here: http://pangea.stanford.edu/~jack/GP170/MarkZoback.pdf you can find that Sandstone, Marble, Limestone and Granite have tensile strengths around 10 MPa. I couldn't understand what you meant by breaking length and how you got 150 to 200 km depth. Could you please explain that so...
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    Will this rope break due to the tidal forces or not?

    But the Earth is not bound only by its gravity, the rocks have tensile strength and so at 10 m/s2, free objects on the surface of the Earth will be floating, but the Earth itself will be bound by its rocks tensile strength. You could arguethat the tensile strength is small compared to the force...
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    Will this rope break due to the tidal forces or not?

    Could you please explain why that would happen ?
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