Is it possible that you used a different number of significant figures than the answer key?
The two values are very close.
Edit:
You shouldn't add the values at the end, you should find the resultant of AC with AB, and then add AD. Is this what you did?
Homework Statement
Find the equation of the tangent line on the function, f(x) = X^{2}-4x+1, which is perpendicular to the line, x+2y=10.
Homework Equations
The Attempt at a Solution
x+2y=10
2y = 10-x
y=-1/2x+5
Slope of perpendicular is -1/2, so slope of tangent is 2.
The...
Yes, it has a higher speed because their momenta are equal (in opposite directions though). Since one mass is smaller, the speed has to be higher, so it will travel further before the force of friction stops it.
Yes, the lighter cart will go further.
And you actually need an equation here: p = mv
They both get imparted with the same momentum, from the spring.
So why does one have a higher speed than the other?
The derivative describes the slope of a tangent to the circle which is perpendicular to the radius... but I don't seem to go anywhere from here... hmmm
Homework Statement
Show that the rate of change of the area of a circle with respect to its radius is the same as the circumference of the circle. Can you suggest why?
Homework Equations
A = \pir^{2} = f(r)
L = 2\pir = g(r)
The Attempt at a Solution
I have showed that the...
That's correct. The definition of power, which is 60 W, is the rate electrical energy is transformed. You don't need to do any calculations. The answer is given.
There are many websites. Look in the forums under the tutorials. Also you can just google for a topic you don't understand.
"and throws a stone horizontally over the edge with a speed of 21.0 m/s"
Horizontal speed is 21. It says horizontally. What is the speed vertically then?
In two...
I don't know why you would make it so complicated.
Speed v is equal to the distance d over time t.
v = d/ t
So t = d/ v
I think you know now why their times are equal.
So for the first guy
t = dx/vx = dx/8
For the second guy
t = dy/vy = dy/5
The times are equal so
dx/8 = dy/5
d is the distance...
I would do it like you did.
These values are very close.
10.2 * 10^12
9.85 * 10^12
So why do you think that is? You and your teacher used different number of significant figures.
3.8 * 10^8
and
2.36 * 10^6
Only two or three significant figures.
Use these values for your calculation and you get...