Compressed spring momentum problem

In summary, when a compressed spring is released between two carts, the lighter cart will travel further due to its smaller mass and higher speed. This is because both carts receive the same amount of momentum from the spring, but the lighter cart has a higher velocity to compensate for its smaller mass.
  • #1
Knfoster
45
0

Homework Statement



Two lab carts, one heavy and one light, are placed ed to end with a large, compressed spring placed between the two carts. The spring is suddenly released. Describe the motions of the two carts after the spring is released.

Homework Equations

An equation isn't needed.



The Attempt at a Solution

The lighter of the two carts would go further right? Why is it that it goes further though, other than it simply being easier to push?
 
Physics news on Phys.org
  • #2


Yes, the lighter cart will go further.
And you actually need an equation here: p = mv
They both get imparted with the same momentum, from the spring.
So why does one have a higher speed than the other?
 
  • #3


Is it simply that the velocity must compensate for the smaller mass?
 
  • #4


Yes, it has a higher speed because their momenta are equal (in opposite directions though). Since one mass is smaller, the speed has to be higher, so it will travel further before the force of friction stops it.
 

1. What is a compressed spring momentum problem?

A compressed spring momentum problem is a physics problem that involves a spring that is compressed and then released, causing it to oscillate back and forth. The problem typically asks for the velocity, acceleration, or position of the spring at a certain point in time.

2. How do you solve a compressed spring momentum problem?

To solve a compressed spring momentum problem, you need to use the conservation of energy principle, which states that the total energy of a system remains constant. This means that the initial potential energy of the compressed spring is equal to the final kinetic energy when it is released. By setting these two energies equal to each other and solving for the unknown variable, you can find the answer to the problem.

3. What are the key factors to consider in a compressed spring momentum problem?

The key factors to consider in a compressed spring momentum problem are the mass of the spring, the spring constant (a measure of its stiffness), and the initial compression or displacement of the spring. These factors will affect the amount of potential and kinetic energy present in the system, and therefore, the outcome of the problem.

4. What are the units used in a compressed spring momentum problem?

The units used in a compressed spring momentum problem depend on the specific variables being solved for. The mass is typically measured in kilograms (kg), the spring constant in newtons per meter (N/m), and the displacement or position in meters (m). Velocity is measured in meters per second (m/s), and acceleration in meters per second squared (m/s^2).

5. Are there any real-life applications of compressed spring momentum problems?

Yes, compressed spring momentum problems have many real-life applications. Examples include the suspension system in a car, shock absorbers, pogo sticks, and even diving boards. These systems use the energy stored in a compressed spring to provide a cushioning effect and absorb impact.

Similar threads

  • Introductory Physics Homework Help
Replies
6
Views
2K
  • Introductory Physics Homework Help
Replies
8
Views
5K
  • Introductory Physics Homework Help
Replies
24
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
2K
  • Introductory Physics Homework Help
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
14
Views
3K
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
850
  • Introductory Physics Homework Help
Replies
3
Views
1K
Back
Top