Recent content by Hydrinium.h2

I found out what I was doing wrong, in |Ff|=4.3(1+x0.5)N N is Newtons not the normal force. If you don't multiply by the normal force, you end up with 2.89=Vf^2 and that gives 1.7 as an answer, which is one of the possible selections. Thanks!

Hi, thanks for the help, but I don't understand what errors you pointed out, could you clarify? 1. Yes, that is the equation that I meant. The problem never specified what x was, but I assumed it was the distance traveled at time (t). 2. Thanks, I won't forget units 3. I used the integral of...

Homework Statement A 2 kg box is moving at 2 m/s, the box is being slowed by friciton such| Ff| = 4.3(1+x0.5) N. What is the speed of the box after moving 20 cm? Homework Equations W=1/2mV^2-1/2mV0^2 W=FΔxCos(θ) 0=N+∑Fy Friction=μN The Attempt at a Solution So I realize that this is a...