Recent content by Hygelac

THis one just seems wierd, I know it should be easy but for some reason I am having trouble with it :( What is the anti-derivative of 7x^-1 ?

Hey, I have a couple of _easy_ questions about hyperbolas, but its been a while since I have worked with them and am not able to look them up in my math book currently...if someone could just get me started in the right direction, I would really appreciate it :) Given the equation of the...

Ok, thanks for all the help :) One last question... lim[x->0]1/cosbx I can sub 0 in for x, can't I? Then, since sinb would be multiplied by 0, it would turn out 0, which would make it 1/0, which would be undefined...?

lim[x->0](tanbx/sinbx) lim[x->0]{(sinbx/cosbx)/sinbx} x cosbx/cosbx lim[x->0](Sinbx/CosbxSinbx) if I cross out the two Sinbx, I'm left with 1/cosbx. This doesn't seem to get me anywhere. Is there a theorm that I am missing? lim[x->0](sin^3(kx)/x^3) lim[x->0](sin[kx]^3)...

Oh, and, another piecewise one he took off 1 point, not full credit but still I don't know what he didn't like about it... Define g(x) = (x^2+x-6)\(x+3) as a piecewise function so that it will be continuous everywhere. My end result was g(x) = (x-2, x>=0) (-x+2, x<0)

I have these two limit problems that I tried to solve, but got them wrong, and the teacher didn't point out what was wrong with them. I don't want to do it on a future test obviously, but I can't figure out what I did wrong with them. Can someone help solve these two problems...

Excuse me for being dumb, but I still can't figure it out. c^2 = 20^2 + (58+x)^2 gives me really hard to work with numbers, I don't think I'm doing it right.

First off, my attached image will make things make sense. I have a triangle (with a 90 degrees corner), I know that the height is 20' and that the length is more than 58'. I need to find out what the length is to the left of the 6' height mark (trying to find the length of the red line). Can...

Whops, it shoudl be f(@) not f(2) So, 5k = (2sin(@))/@ k = [(2sin(@))/@]/5 Would that work, or did I totally miss your point?

Thanks a bunch :)

Hi, I have just one more problem :) here it is: (because I don't know how to do theta, "@" will equal theta) Find a value of K so that f(2) is continuous at @=0 ( != means "not equal") f(@) = ( (2sin@)/@ , @ !=0 ) ( 5k , @=0 ) f(@) is a piecewise function I don't know...

Thanks for your help, I just thought of something else, too. Seems like this works and is very easy, could you do just a quick check of it and see if it makes sense? f(a) = b, g(b) = c, h(c) = d lim[x->a](h(g(f(a)))) = d f(a) = b, so g(f(a)) = g(b) g(b) = c, so h(g(b)) = h(c) h(c) =...

I'm stuck on one complicated limits problem, wondering if any of you could help me :) usually I am pretty fine with limits but this one uses all variables and has functions in it. Anyways, here it is: f(a) = b, g(b) = c, h(c) = d prove lim[x->a](h°g°f)(a) = d (° = "of") Can anyone...