The answer was 119 apparently. I don't even know why. Maybe my sketch is just extremely difficult to interpret? Blah.
Anyway, thanks for the time and input. At least I have the raw calculation part down.
Thanks a bunch.
It's a multiple choice problem with the choices being:
90
119
151
61
29
I've already tried 2 answers, forfeiting 50% of the potential credit. Is it possible that it is 151 degrees? That is 61+90 degrees... Or 119? 180 - 61?
God I hate Mastering Physics. They gave us a free trial for it as...
That part I do know how to do. But if I crossed vectors A and j, wouldn't I just get a vector in some form of i + j + k? How would I calculate an angle from that?
Well like vela posted the cross-product formula is LaTeX Code: |\vec{A} X \vec{B}| = |A||B|sin \theta
But I only have a vector A? Or can I use components of vector A in that formula?
To be honest, I don't know what formula to use and I don't even know if I can use the y-axis as a vector.
I don't want the answer... I just want to know where to start and what procedure I should use.
I'm pretty confused.
How to find the angle between an XYZ vector and the y-axis? Please help!
Homework Statement
A vector is given as follows:
A = 2i - 2j - 3k
The angle between A and the y-axis is, in degrees, closest to?:
90
119
151
61
29
Homework Equations
c = ab sin\theta ?
The...