Recent content by ibazulic

true, my mistake about that one. now when i reread the first comment again, i see your point :-) thanks. one more question: are indicies in the 2nd and 3rd term correct? now that i look at it, it seems they aren't but I'm not sure.

Caroll defines the covariant derivative as follows: \nabla_\mu V^{\nu} = \partial_{\mu}V^{\nu}+\Gamma^{\nu}_{\mu\sigma}V^{\sigma} (formula 3.2 on page 93) :when i wrote the formula in my first post, i omitted the vector field, just gave a definition on what ##\nabla_{\mu}## is. that's why i...

Hello all, I'm trying to calculate a commutator of two covariant derivatives, as it was done in Caroll, on page 122. The problem is, I don't get the terms he does :-/ If ##\nabla_{\mu}, \nabla_{\nu}## denote two covariant derivatives and ##V^{\rho}## is a vector field, i need to compute...

an eigenstate is a vector whose purpose is to describe the (complete) state of the system. that's because pure wave functions do not have the whole information of the system. for example, one could look at the same system using different wave functions: position, impulse, angular momentum etc...

if I'm reading this correctly, then yes. observables are indeed physical properties that can be measured. for example, if we seek total energy of some eigen-state |\psi> then we will use a Hamiltonian operator to masure that total energy: H|\psi>=E|\psi> which gives us a Schroedinger...