Recent content by ibnuts

Yes, it is an easy problem which I made a mistake on, as I've said before, so stop posturing you a**. I wouldn't be bragging about living in a place that smells like crap where you'll make 1/30th of what I will haha.

Thanks for all the replies. The reason I was upset was because it did make me feel like I had done something wrong. Also, if the college HW usuallly is only for problems that require diff eqs then almost my entire class wouldn't be considered college physics. Then again, there are people...

Yes, it was a simple problem that I complicated by making a mistake. However, it's still a college class. The fact remains you don't send someone in college to get tutored for Algebra at the Elementary school because they never learned it properly. They go to the college math center. With...

Thanks for the reply, but he didn't make it a trick question. I just screwed up by swapping around my values. BTW, should I post a question about another problem in this thread or in a new thread? Also, if I should post in a new thread, should I post in college or k-12, because someone...

Yeah, I swapped them by accident. I've finally gotten the right answer now with everyone's help though! Thanks!

Thanks very much both whozum and Bystander. My problem (and probably my friend's, too) was that I had P_i, which was the largest quantity, in the denominator rather than the numerator **stupid me.** That's what 6 hrs of physics HW does to you when you haven't taken your Adderall :biggrin:

Yeah, I converted back to cm^3. Also, I know the pressure under water is far higher, but shouldn't this mean the volume should increase as the bubble rises to the surface because it's under decreasing pressure? When I plug everything in, I get 0.152 mL as my V_f, which is far lower than the...

That's okay. I edited too fast with link, obviously. Still, the rest of it stands. Why would the V_f be lower than the V_i. If you want, btw, I can direct you to the website that has this. My course website has guest log in.

I thought 1 Pa was 1 N/m^2, which is the product of density*height*gravity = pressure EDIT: found http://www.unc.edu/~rowlett/units/dictP.html#pascal, Pa is in fact SI unit of pressure. I don't think it would matter though, because if you divide both P_f and P_i by 101.325kPa (the...

that's in Pa. I tried at one point converting to atm and it didn't work, but I'll try again just to make sure. I seem to be getting different answers using the computer calc than with my TI-89 anyway, so I'll just make sure.

I'm also wondering about this formula, which is in fact what I used before and got wrong. Using the pressure formula, the P_f will be far higher than the P_i , meaning the final answer for V_f will be very low (dividing a small # by a very large #). This doesn't make sense though since...

I was wondering why my thread was moved from College HW to K-12 HW. I'm a sophomore in college and this is calc-based college physics HW.

That's exactly what I did, and I got the answer wrong. By the way, how did you get the Pi etc to show like that? Also, to whoever the ops of this site are, this is College HW NOT K-12 EDIT: Don't worry about explaining the Pi, I clicked on message and got the .pdf file explaining how-to.

Yup. I did the following: PiVi/Ti = PfVf/Tf => Vf = (Tf/Ti)*(Pi/Pf)*(Vi) =(Tf/Ti)*((Pi)/((Pi)+(density of sea water*gravity*initial depth of water)))*(initial volume of bubble) = (293.15/278.15)*((1.013*10^5)/((1.013*10^5)+(1025*9.8*80.0)))*(1.00) =[my answer was wrong] Note: I...

Hey, my friend and I have worked on this problem for about 2 hours straight (from our online HW) and can't get the answer right. The help offices and the professor are closed/gone for the weekend. Can anyone please help?! :eek: At 80.0m below the surface of the sea (density = 1.025g/cm3)...