With the new setup as you've described, I got:
A(t) = 15.75-0.045t - C/exp[-4*ln(350-t)]
C = 3.50e-10
A(t) = 15.75-0.045t - (3.50e-10)/exp[-4*ln(350-t)]
A(60) = 3.65%
Does that sound about right?
Thanks! I think I'll just plug in those values and make it easier, then. I think I just accidentally split it up as if r were the same throughout the problem when I tried to solve symbolically.
Homework Statement
Beer containing 6% alcohol per gallon is pumped into a vat that initially contains 350 gallons of beer at 3% alcohol. The rate at which the beer is pumped in is 3 gallons per minute, whereas the mixed liquid is pumped out at a rate of 4 gallons per minute. Find the number of...