Recent content by IhasSwag

  1. I

    Why does the hung mass balance the bar's moment, not the opposite side?

    I meant the mass of the bar on the right side of the center of mass
  2. I

    Why does the hung mass balance the bar's moment, not the opposite side?

    The mass of the bar on the right side?
  3. I

    Why does the hung mass balance the bar's moment, not the opposite side?

    They cancel out at the center of mass?
  4. I

    Why does the hung mass balance the bar's moment, not the opposite side?

    I see now that it is (15 + x ) / 2 - x
  5. I

    Why does the hung mass balance the bar's moment, not the opposite side?

    is it: 15 - (15+x)/2 ?
  6. I

    Why does the hung mass balance the bar's moment, not the opposite side?

    I really don't know
  7. I

    Why does the hung mass balance the bar's moment, not the opposite side?

    isn't the center of mass exactly in the middle?
  8. I

    Why does the hung mass balance the bar's moment, not the opposite side?

    the bar is 15cm on the right side. The mass is 3 grams / cm. So 45 grams.
  9. I

    Why does the hung mass balance the bar's moment, not the opposite side?

    Homework Statement The bar has a mass of 3 grams/cm. When a mass of 15 grams is hung on the left side, the system is balanced. Calculate the length of the bar. Homework Equations F1*r1 = F2*r2 The Attempt at a Solution I thought that the moment on the left should be equal to the moment at the...
  10. I

    Relation between masses in a three-mass pulley system at rest

    The rope is indeed not massless. Thank you very much for your help.
  11. I

    Relation between masses in a three-mass pulley system at rest

    I meant to say that the rope has mass
  12. I

    Relation between masses in a three-mass pulley system at rest

    It doesn't state that the rope is massless, so I guess not.
  13. I

    Relation between masses in a three-mass pulley system at rest

    If T1 = T3 then m1 = m3 This means that m2 = 2*m1 ? But now I face another problem because according to my teacher, the answer should have been: m2 < 2*m1
  14. I

    Relation between masses in a three-mass pulley system at rest

    So T1 + T3 - m2*g = 0 ? m1*g + m3*g = m2*g m1 + m3 = m2 ? Am I approaching this problem the right way now? I found out that I made a mistake in the possible answers. It should be: mblock2 = 2*mblock1 mblock2 > 2*mblock1 mblock2 < 2*mblock1
  15. I

    Relation between masses in a three-mass pulley system at rest

    Homework Statement Find the relation between the mass of block 1 and the mass of block 2. Assume that the pullies are massless and frictionless and that the rope is inelastic. All masses are unknown. Possible answers: mblock2 = mblock1[/B] mblock2 > mblock1...
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