Recent content by ImpCat

I would reply that in a series circuit, there would only be one path for electrons to flow. Whereas in this particular circuit diagram, there are two paths for the current to flow toward the resistors-as seen by the wire connecting the sides of the resistor and in between the resistors. As such...

By treating it as a parallel circuit so 1/10 + 1/10 = 1/r r=5

Thanks for the picture, really helped my understanding :smile:

I see now, thanks for your help! The answer would then be B. It's just that the phrase "Resistance between PQ" confused me. Like how can you have a resistance between two points, don't you need a sort of conductor?

I realize that, I just treated PQ as a resistor-which I realize is a big mistake. But if I don't treat it as a resistor, how would I find the resistance between PQ?

A series arrangement would be where the resistors are connected next to each other. Parallel would be where the path of the resistors are divided. So the unknown resistor and 1 of the known resistor are in parallel. There is also one known resistor of 10ohms that are in series to the parallel...

So since the known resistors are in a series, do I just add them together to get the unknown resistance? I'm really confused ._.

I still have no idea, I tried totaling the resistance on the parallel resistors (Rtotal) and treat it as a series with the 10ohms resistor. I then assumed that the current that passes out of the 10ohms resistor is equivalent to the current into the parallel resistors: Current out of 10ohms...

Actually, I used v1 both times as the two resistors provided are of the same ohms, and I was too lazy to change its symbol. So you can treat one of the v1 as vb or vy. Sorry for the confusing equations xD. Also, I did convert the circuit into a series, by adding the parallel resistors together...

The unknown resistor and 1 of the known resistor are in parallel, but on the whole both are in series with another known resistor. Yet I still don't understand how to convert all of these into the value of the unknown resistor. :(

As in a series, the total resistances are simply added up, and in parallel, the resistances are added up by 1/r1 +1/r2 = 1/rTotal. So if I added up the parallel resistors and pretend it is just 1 resistor with a resistance of 1/(1/r1 +1/r2)=rX, then the total resistance in the circuit would be...

In parallel, the resistors combine by the rule 1/r1 +1/r2 = 1/rTotal, in series the resistors combine by r1+r2=rTotal. So the net resistance in this circuit would be rTotal= r1+ 1/(1/r1 +1/r2)

But how would I know the resistance just from the resistance of the other two resistors?

They have the same voltage across both resistors? But the voltage across the two resistors is after the voltage has been reduced by the first resistor right? I still am not seeing how I can solve the equation with just these information. :<

Homework Statement Homework Equations R=V/I The Attempt at a Solution Would it be 10ohms? Since PQ is between two 10ohms resistor.