updated
X=VXoT=Vo COS 25 degrees T = Vo(.91)T
Y=VYoT-1/2 g(t)sqrd=Vo SIN 25 degrees = Vo.42)T - 1/2g(t)sqrd
so then you're saying
X=6.02=V(6.02)(.91)T
X=5.46VT
Y=Y0+VYoT-1/2 g(t)sqrd
Y=(2.05)+V(2.05)T-1/2g(t)sqrd
Y=2.05+V(2.05)T-4.9(t)sqrd
Okay...am I heading in the right direction...
May I first of all prelude this by saying that Physics has been a huge challenge for me. So, baby steps please.
Homework Statement
2.05-m-tall basketball player takes a shot when he is 6.02 m from the basket. If the launch angle is 25 degrees and the ball was launched at the level of the...