This is what I did:
q/m = vB┴r
(1.10 x 10^4 C/kg)(9.10 x 10^-1 T)(0.420 m) = v
v = 2402.4 m/s
C = (pie)d (I don't know how to make the symbol)
C = (pie)(0.480 m)
C = 1.507...m
t = d/ = 1.507...m/2402.4 m/s = 6.28 x 10^-4 s
Is this right?
Hi, I need help with this question:
An ion with a charge-to-mass ratio of 1.10 x 10^4 C/kg travels perpendicular to a magnetic field (B = 9.10 x 10^-1 T) in a circular path (R = 0.240 m). How long does it take the ion to travel one revolution?
I've found the speed that it travels...then...