Recent content by iva

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    Does the integral of x^(3/2) sin(2x) converge over the range of 0 to 1?

    having said this , that function converges towards the origin.. guess maybe i just need to mention all these properties that I believe the function to have.
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    Does the integral of x^(3/2) sin(2x) converge over the range of 0 to 1?

    Actually, would this reasoning make sense: since the |sin t| =< 1 as the value of x increases the x3/2 part will inflate the wave increasingly, so that it continuous to oscilate but gets bigger and bigger, therefore being monotone diverging? I found an image for what I'm trying to describe...
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    Does the integral of x^(3/2) sin(2x) converge over the range of 0 to 1?

    I agree, but the question specifically asks us to discuss the convergence of this function. If there was no integral and it was a series i would say that the series is monotone,bounded by 0 and 1 and divergent as it never decreases but oscilates; but as it's a function I'm not sure. Clearly it...
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    Does the integral of x^(3/2) sin(2x) converge over the range of 0 to 1?

    Homework Statement Discuss the convergence of Integral(x3/2 sin 2x dx) range is from 0 to 1Homework Equations|sin x| =< 1 The Attempt at a Solution The sine function converges absolutely. It is also increasing from 0 to 90 degrees, decreases until 27 decrease and it is negative from 180 to...
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    Does Pulley Mass Affect Rope Tension Symmetry?

    Thanks yes i got the rotational equation when i started working this out but then got confused with the tensions , wanting to make the tension for both sides the same as well as the accelerations, but now it makes sense. The pulley system is not as intuitive or straight forward as I thought it...
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    Does Pulley Mass Affect Rope Tension Symmetry?

    So if the acceleration is the same either side, then what this means is that the Tension is a result of the pulley mass PLUS each of the block masses separately?? Sort of like T1 = (Mass block1 + mass pulley) * linear acceleration and T2 = (Mass block2 + mass pulley) * linear acceleration...
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    Does Pulley Mass Affect Rope Tension Symmetry?

    Thanks, OK i realize I'm mixing up and confusing friction with slipping ( as I've just learned about the slipping factor that if there is no slipping then linear acceleration is related to angular acceleration by radius * angular acceleration) So if there is no slipping of the rope on the pulley...
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    Does Pulley Mass Affect Rope Tension Symmetry?

    Thanks, but do you still need to consider Torque even if there is no friction on the rope going over the pulley? I'm just thinking that if you have this pulley that just rolls easily (I'm thinknig of some sports equipment where often the rope doesn't go over the pulley because there is dirt on...
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    Does Pulley Mass Affect Rope Tension Symmetry?

    Hi there, If a pulley system made of 2 same mass blocks (on a a table, one hanging), a disk pulley with mass but no friction on the string nor pulley axis, does it mean that the Tension on the rope is the same on either side of the rope? Everywhere I've read implies this, and it makes sense...
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    Find moment of Inertia from Force, radius and acceleration

    Thanks i get it now, So all i really needed was 1 equation: rotational force equation: r* F=I * alpha so I=rF/alpha right?
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    Find moment of Inertia from Force, radius and acceleration

    Homework Statement A disc shaped object is made of a non-uniform material. Its radius is r and it is fre to rotate about an axis through its centre. If a force F applied tangentially at the edge of the object produces the angular acceleration a, what is its moment of inertia for rotation...
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    How Is the Moment of Inertia of a Cube Calculated Incorrectly?

    Because a suitable axis would have to be one that goes through the COM right? Thank you so much your help was great, having the answer infront of me led me to not think about each step
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    How Is the Moment of Inertia of a Cube Calculated Incorrectly?

    Oh i see, I jumped a step because i knew the result, is it because for the lamina that Iz would be going through the COM of the cube, then you just sum up all the little masses of the slices geting 1 big mass for the cube?
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    How Is the Moment of Inertia of a Cube Calculated Incorrectly?

    Just realized ( maybe ) Could the MoI on this lamina be seen as the Ix or Iy for the cube, ie i could use the perpedicular axes theorem by using this lamina result as the x-axis MoI, double it as it will be the same being a cube and that is where i would get MA^2/6 ?!
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    How Is the Moment of Inertia of a Cube Calculated Incorrectly?

    AAAAH I see, but now I'm stumped, i can't use the parallel or perpedicular axis theorems because like you've pointed out that MoI waas taken for a sheet on the face of the cube . BUT can't i say that the sheet was taken from the centre of the cube? the laminas will be the same through out right?
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