Recent content by izic

Alright, I tried that but ended up with (k+1)(2^(k+3)) instead of (k+1)(2^(k+3)+2)). How can I get the "+2" part? http://i49.tinypic.com/25q6g51.png

Added them together but it's equaling the right hand side. http://i50.tinypic.com/33dfbls.png

I notice that after distributing it, I get k*(2^(k+2)) + (2^(k+3)) (2^(k+2)*k) Do you mind explaining how to get these bold parts in the RHS (2^(k+3)+2)[B](k+1) from the left hand side which is this k*(2^(k+2))+ (2^(k+3)) (2^(k+2)*k)?

First I get, (k * 2^k *2^2 + 2)+ (k+2)(2^k* 2^2). Then, (2^k * 2)(k+2) +(k+2)(2^k * 2) Can I factor out one "(2^k * 2)(k+2)" since I have two of them?

Oh so that's what I was missing. But yeah I took what you gave me and I was able to get the Left hand side to look like "(k+1)(k+2)(2^k+3)" which is close to the right hand side "(k+1)(2^k+3)". Did I go about this the right way? All I need to do is cancel (k+2) and the left hand side will...

Alright so I broke the summation up into three parts - i=1, i=k+1, and i=k+2 and since I already knew what i=k+1 and i=k+2 was, I plugged those values for it. This is what I have so far but to be honest I'm not sure how to go where from here. http://i45.tinypic.com/5158xu.jpg

Hi, I'm currently taking Discrete Mathematics and I'm working on a mathematical induction problem that's a little different than usual because it has a summation in it. What I basically want to know is did I do parts A and C correctly? Homework Statement Homework Equations The Attempt at a...