Recent content by J--me

Oh right so the general solution is just y(2) = -x exp(1/x) Thanks! (Where did i lose a solution?? =S)

Cool! Thanks! =D! So the integration of that is g = f' so: f = INT (g) dt = -exp(1/x) what do i do now to get the general solution?? =S

>.<! I may need a fourth try.. Ok so ln(a-b) = ln(a/b) sooo: 0 = 1/x - ln(x^2) - ln(g) 0 = 1/x - ln(x^2/g) Therefore: g = x^2 exp(-1/x) ? =S but if i use ln(a+b) = ln(a*b) then i get: g = x^-2 exp(1/x) ? =S! o.O (sorry if I am doing something really silly!)

Hey! Lol! Thanks! Should g = -x^2 exp(1/x)?

Reduction of Order ODE - Stuck on question! Help Please! The question says that y1= x is a solution to: x^3 y'' + x y' - y = 0 It then says to use y2 = y1 f(x) So I can do it this far and then I just get lost and my notes don't seem to clear anything! I'm just going to say y(2) = y2...

E(mech) = E(pot) + E(kin) E(kin) = 1/2mv^2 = 1/2m(A^2-x^2)w^2 = 1/2k(A^2-x^2) E(tot) = 1/2kx^2 + 1/2k(A^2-x^2) therefore the equation simplifies to give you one formula

If he doesn't stop swinging back and forth then his mechanical energy is conserved but if he stops then his swing is being dampened, but in this case i would say that his mechanical energy is conserved.