So after Newtonian mechanics and electricity/magnetism, what do physics majors study? Also, is there a textbook you can reference me to that applies to that?
1.) So first I differentiate and set it equal to 0 and get:
$$\frac{A}{r^2} -\frac{Bn}{r^{n-1}} = 0$$
2.) When solving for r, I'm not quite sure how to take away the exponent so I get up to the second to last step:
$$r^{n-3} = \frac{Bn}{A}$$
Would it be:
$$r = \sqrt[n-3]{\frac{Bn}{A}}$$
...
Thanks for showing me a much simpler way. I think it's because they would cancel each other out. For example, taking the integral you'd end up with some constants times ##z^4 - z^4## which would give you zero. I think.
Hi I wanted to revisit this and finish the problem to see if my reasoning skills have improved since.
So to start I think it's important to define ##q_{enc}##. We are given ##\rho## as a function of z. ##\rho## has the constant in it with units of C/m^5 with z^2 over it which has two...
I know we're supposed to attempt a solution but I'm honestly super confused here. I think the second an third terms of the del equation can be cancelled out because there is only an E field in the r hat direction, so no e field in the theta and phi directions. That leaves us with ##\nabla \cdot...
You're right. I explained that poorly.
The gain is the voltage across the resistor over the total voltage which is 0.5
$$\frac{V_R}{V_t} = 0.5$$
$$V_R = iR$$
$$R = 8$$
Rearranging gives,
$$\frac{V_t}{i} = \frac{8}{0.5} = 16$$
My reasoning is that because half of the voltage goes across the resistor which is 8 ohms the other half must go across the inductor and capacitor making the total impedance 16. The current is constant throughout an entire series circuit
Not sure what I'm doing wrong. When I set up a system of equations for L and C, I don't see how having two frequencies makes a difference. Am I on the right track at least or no?
$$\sqrt{8^{2} + (X_L - X_C)^{2}} = 16$$
$$X_L - X_C = \sqrt{192}$$
$$\omega L - \frac{1}{\omega C} = \sqrt{192}$$...
I understand. I'm just confused about how to find the two unknowns. I got 16 ohms for the impedance. Do I need both frequencies to solve for the the two unknowns?
So we know that half the voltage is taken up by the resistor which means the other half has to be taken up by the inductor and the capacitor so I came up with this:
$$L\frac{dI}{dt} + \frac{Q}{C} = 0.5V_{0}sin\omega t = iR$$
The question says the the circuit is at resonance so that means ##X_L...