Recent content by jaci55555
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J
Prove a^n - a is multiple of n
yay, got it all! thank you for all your help everyone! i'd put up the soln but you all had it ages ago :P- jaci55555
- Post #25
- Forum: Calculus and Beyond Homework Help
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J
Connection between roots of polynomials of degree n
:) you rock my world! are you really still in high school?- jaci55555
- Post #6
- Forum: Calculus and Beyond Homework Help
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J
Prove a^n - a is multiple of n
before i can suppose this, i need to prove it true for a^5 - a... which i haven't got yet i think it'll work for every n prime- jaci55555
- Post #23
- Forum: Calculus and Beyond Homework Help
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J
Prove a^n - a is multiple of n
my computer doesn't let me see your replies until i post something. very frustrating- jaci55555
- Post #21
- Forum: Calculus and Beyond Homework Help
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J
Prove a^n - a is multiple of n
ooh, didn't see your reply! yes, you're right, just fixed it- jaci55555
- Post #16
- Forum: Calculus and Beyond Homework Help
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J
Prove a^n - a is multiple of n
no, (a-1)^5 = a^5 - 5a^4 +10a^3 - 10a^2 + 5a -1- jaci55555
- Post #15
- Forum: Calculus and Beyond Homework Help
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J
Connection between roots of polynomials of degree n
algebrat: at n=1 it is just the reciprocal at n =2 it's: x_1 = (a_1 +- sqrt(a_1^2 -4a_2a_0))/2a_0 and x_2 = (a_1 +- sqrt(a_1^2 -4a_2a_0))/2a_2 so everything above the line is he same, just the a_0 and a_2 change i'll find a formula for n =3 and try that... dick: i tried this, but don't see...- jaci55555
- Post #4
- Forum: Calculus and Beyond Homework Help
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J
Prove a^n - a is multiple of n
thanks dickfore, but Dh is right, it's just to figure out if there is any generalization :) thanks tho! Algebrat: It's a post-grad class where they give us random problems to set to young children in an understandable way DH: (a+1)^5 = a^5 + 4a^4 + 6a^3 + 4a^2 + a^1 so we have the a^5 and...- jaci55555
- Post #13
- Forum: Calculus and Beyond Homework Help
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J
Connection between roots of polynomials of degree n
Homework Statement The two polynomial eqns have the same coefficients, if switched order: a_0 x_n+ a_1 x_n-1 + a_2 x_n-2 + … + a_n-2 x_2 + a_n-1 x + a_n = 0 …….(1) a_n x_n+ a_n-1 x_n-1 + a_n-2 x_n-2 + … + a_2 x_2 + a_1 x + a_0 = 0 …….(2) what is the connection between the roots of...- jaci55555
- Thread
- Connection Degree Polynomials Roots
- Replies: 6
- Forum: Calculus and Beyond Homework Help
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J
Prove a^n - a is multiple of n
Homework Statement Prove that a^3 - a is a multiple of 3 a^5 - a is a multiple of 5 Generalise … to a^n - a a multiple of n Homework Equations The Attempt at a Solution a^3 - a = a(a^2 - 1) = a(a+1)(a-1) thus three consecutive numbers are multiplied. if three numbers are...- jaci55555
- Thread
- Multiple
- Replies: 24
- Forum: Calculus and Beyond Homework Help
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J
Proving Convergence of sum[n=0 to inf] (z+2)^(n-1)/((n+1)^3 * 4^n) for |z+2|<=4
so i remove the lim and then |Z+2|<4, but i still need it to be equal to 4 as well- jaci55555
- Post #7
- Forum: Calculus and Beyond Homework Help
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J
Find Entire Functions for f(2-i)=4i and |f(z)|≤e^2
thank you- jaci55555
- Post #7
- Forum: Calculus and Beyond Homework Help
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J
Proving Convergence of sum[n=0 to inf] (z+2)^(n-1)/((n+1)^3 * 4^n) for |z+2|<=4
So then lim(n->inf) (z+2)/4 <1 so that lim(n->inf) (z+2) <4 but i need to find find <=4- jaci55555
- Post #5
- Forum: Calculus and Beyond Homework Help
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J
Proving Convergence of sum[n=0 to inf] (z+2)^(n-1)/((n+1)^3 * 4^n) for |z+2|<=4
Thank you for answering, I'm still figuring LaTeX out :) so should i use what i did, and then the ratio test? I did this and got lim (0-> inf) ((n+1)^3/(n+2)^3), are there any steps i should put after this, or is it fine that i can see that this is <1 ? Thanks again for you help!- jaci55555
- Post #3
- Forum: Calculus and Beyond Homework Help
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J
Find Entire Functions for f(2-i)=4i and |f(z)|≤e^2
Thanks for answering :) That is all the question stated - so i think it does hold for all z. I thought the theorem i stated above WAS Liouville's theorem? But i wasn't sure about how to use it.- jaci55555
- Post #5
- Forum: Calculus and Beyond Homework Help