Recent content by jack343

Because its 6.89m/s @ 15.0deg, you can use trigonometric functions to find the initial vertical and horizontal speed: vertical: sin(15.0) = o / 6.89 horizontal: cos(15.0) = a / 6.89 Since the horizontal velocity is constant as gravity does not affect it, the time the projectile is in...

I lost another battle... deffered from my top school :/ anyhow, thanks for the help, in return I will help someone else.

THANK YOU SO MUCH! I FIGURED IT OUT :) Unfortunately, I bombed my electrostatics test today... great way to start winter vacation. :(

Thanks, now I know where the forces are going. But why is sin(theta) = d/2L? shouldn't it be cos(theta) since L is the adjacent side? Can't we use the Pythagorean theorem to get that r = sqrt(L^2 + (d/2)^2) ?

Homework Statement Two equal and opposite charges form a dipole, as shown in the figure. What is the magnitude of the electric field at point P, in terms of k,q,d, and x? If point P is VERY far away, show that the result is approximately E = kqd/x^3...