Recent content by jackjoo87

dr(H3)=N(air)/N(He) dr(air)/Sa 2x N(air) at 1 atm=N (He) at 2 atm. thus, dr(H3)=1/2 dr(air)/0.36. dr(air) i get from the curve.. am i correct?

thank you very much for your help Bob S... :) am i suppose to use equation from Pg 652 (eq 3.14)? because the book give us the relative atomic stopping power ratio...

thanks for your reply, Bob S. I already calculate the answers for a(1.33) ,b (0.165), and c, KE(alpha)=2.0541 MeV); KE(H3)= 2.7259 MeV. For question d, how mean length of alpha particle changes with pressure within the chamber? can i get directly from the curve Fig. 3.2?

Li6(n,a)H3 , Q = 4.78 Mev. The H3 and He4 products are oppositely directed, away from the site of the compound nucleus, and hence they form one straight track. How to calculate the mean range of the alpha particle if the atomic stopping power of helium realtive to air is given as 0.36?

a nuclear reaction Q value is the difference in kinetic energy of the final particle and the initial particle. how we can determine the kinetic energy only for the recoil nuclei if the kinetic energy of other particles are not given?

reaction B10(n,alpha)Li7, Q=2.79Mev. the He4 and Li7 are oppositely directed away from the site of the compound nucleus and form one straight track. a) what is the initial kinetic energy (KE) of He4? b) what is the initial KE of Li7 nucleus? c) estimate the ratio of the specific ionization...