Recent content by JACKR

Ofcourse

Yep, Why isn't it correct?

Why not?

I am saying that V1=V2 since the emf induced in the rod is the same for both cases equal BLv. Am I correct?

I did study it yes. The word atoms isn't mentioned anywhere there because he called them 'resonators' instead. You know, the idea that matter is composed of atoms wasn't something popular back then. However, these resonators turned out to be what we call today atoms! So, as you can see from the...

Planck, M. On the Law of Distribution of Energy in the Normal Spectrum.

Yep I know this. What I am asking about is, does υₛ refer to anything about the atom to which the electron is attached? I mean, removing an electron from an atom result in forming a positive ion with an energy greater than the energy of the original atom by an amount equal to hυₛ. My question...

The equation KE=hυ- hυₛ gives the maximum energy an electron can acquire when a photon with a frequency υ is incident on the cathode. I am wondering what does υₛ refer to? Does it mean the frequency of the atom to which the electron is attached? According to Planck, the smallest energy an atom...

Thanks for pointing them out. Yeah, I managed parts (e) and (f); thank you!

(a) The potentiometer is set at R = 3.20 kΩ and there is a NO photocurrent. What is the potential difference VAC? It's a a typo in the statement of the question.

Regarding part (b), you can think of it as the moment just before the one moment when current flows. Indeed, this is only way to solve the problem. Also, the value calculated there is the value of the stoping potential. About the equation, I think you're right. I shouldn't have put a modulus...

But why would you assume that it's still set at 334 Ω?

(a) is easy. No i. Therefore, the 1kΩ resistor and the 3.20kΩ one are connected in series. So 'I' can be easily determined and so is VAC (b) is the same as (a) (c) The work function should be solved for via the equation eV₀=hυ-φ, where V₀ is the absolute value for VAC from part (b) (d) I am...