Recent content by jackster18

  1. J

    Exploring Effects of Magnets on TV Screens

    i can't find anything on U-turns of electrons in magnetic fields
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    Exploring Effects of Magnets on TV Screens

    Homework Statement A strong magnet is placed on the screen of a television set (permanently damaging the tube). Explain the following observations. a) the picture becomes distorted b) the screen is completely dark where the field is strongest Homework Equations none. The Attempt...
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    Cost of Rest Energy of 1.0 Kg at $0.60/kWh

    Homework Statement How much would the rest energy of a 1.0 Kg mass cost at the typical utility rate of $0.60/ kWh? Homework Equations E=mc^2 The Attempt at a Solution Heres what somone told me from another website: "The rest energy of a mass is the energy calculated by E=mc^2...
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    The Energy in the World's Oceans: Calculations and Consequences

    Homework Statement Approximately 1.0 X 10^34 J of energy is available from fusion of hydrogen in the world's oceans. a) If 1.0 X 10^33 J of this energy were utilized, what would be the decrease in the mass of the oceans? b) To what volume of water does this correspond? Homework...
  5. J

    How much work must be done to carry a +2.3 X 10^-3 C charge from 65 cm to 15 cm?

    oh u mean by two significant figures the "31" part of the number?
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    How much work must be done to carry a +2.3 X 10^-3 C charge from 65 cm to 15 cm?

    im not smart enough to see that each way is identical, i guess by looking at the units and cancelling them out?
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    How much work must be done to carry a +2.3 X 10^-3 C charge from 65 cm to 15 cm?

    I guess doing it this way: "Using the equation ∆Ee=Kq1q2(1/r2 - 1/r1) ∆Ee=Kq1q2(1/r2 - 1/r1) =(9.0 X 10^9 Nm^2/C^2)(3.0 X 10^-5 C)(+2.3 X 10^-3 C)(1/0.15 cm -1/0.65 m) =3184.62 J" is better because i am not using numbers that i calculated from before which could create errors.
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    How much work must be done to carry a +2.3 X 10^-3 C charge from 65 cm to 15 cm?

    yes, it is just rounding error, i used the exact value of V1= 415384.62 V and got the answer 3184.62 V, thanks for helping :)
  9. J

    How much work must be done to carry a +2.3 X 10^-3 C charge from 65 cm to 15 cm?

    ok so from a) the part where the radius is 0.15,I got v=1.8 X 10^6 V, when the radius is 0.65 m i got V= 4.2 X 10^5 V... so i guess...∆V=V2-V1...and in part b r1=0.65 m (where v1= 4.2 X 10^5 V) and r2=0.15 m (where v2= 1.8 X 10^6 V)...so i just go: ∆V=V2-V1 =1.8 X 10^6 V - 4.2 X 10^5 V =...
  10. J

    How much work must be done to carry a +2.3 X 10^-3 C charge from 65 cm to 15 cm?

    That is exactly what it says on the sheet for the questions.
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    How much work must be done to carry a +2.3 X 10^-3 C charge from 65 cm to 15 cm?

    Here’s the entire question, yes there is two parts, but it doesn’t make sense to me why you would use this from the other question. 1.a) What is the electric potential from a charge of 3.0 X 10^-5 C at 15 cm and 65 cm? b) How much work must be done to carry a +2.3 X 10^-3 C charge from 65 cm...
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    How much work must be done to carry a +2.3 X 10^-3 C charge from 65 cm to 15 cm?

    Homework Statement How much work must be done to carry a +2.3 X 10^-3 C charge from 65 cm to 15 cm? From the question: q=+2.3 X 10^-3 C r1= 65 cm = 0.65 m (these must be converted to metres) r2= 15 cm = 0.15 m k= 9.0 X 10^9 Nm^2/C^2 W=? W=∆Ee ∆Ee=q∆V (I'd just like to say that...
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    Exploring the Effects of Changing Universal Gravitational Constant

    We also took some cool vids of of youtube about space, black holes and stuff and the teacher liked it, also we made a newreport video saying what was going to happen. Heres the websites if you want to see the videos im only able to post urls after 15 posts :( that's no good.
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