Cost of Rest Energy of 1.0 Kg at $0.60/kWh

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SUMMARY

The cost of the rest energy of a 1.0 Kg mass is calculated using Einstein's equation E=mc², resulting in 9E16 Joules. Converting this energy into kilowatt-hours (kWh) at a utility rate of $0.60/kWh yields a total cost of approximately $15 billion. The conversion from Joules to kWh is achieved by using the factor 1 kWh = 3.6E6 J. The calculation involves multiplying the energy in kWh by the cost per kWh to determine the total expense.

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Homework Statement



How much would the rest energy of a 1.0 Kg mass cost at the typical utility rate of $0.60/ kWh?

Homework Equations



E=mc^2

The Attempt at a Solution



Heres what someone told me from another website:

"The rest energy of a mass is the energy calculated by E=mc^2 when the mass is at rest.

E = (3E8 m/s)^2 * 1kg = 9E16 J

1 kWh = (1000 J/s)(3600 s) = 3.6E6 J

Energy * Cost/Energy = Cost
(9E16 J) * (1 kWh / 3.6E6 J) * ($0.60 kWh) = 15 billion dollars"

but i don't understand the last part, where they multiply (9E16 J) * (1 kWh / 3.6E6 J) * ($0.60 kWh). The eprson said Energy * Cost/Energy = Cost, so wouldn't that just be (9E16 J)(($0.60 kWh)/(9E16 J))?
 
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Hi jackster18,

The first two terms

<br /> (9\times 10^{16} \mbox{ J}) \times \left(\frac{1 \mbox{ kWh} }{ 3.6\times 10^6 \mbox{ J}}\right)<br />

converts the energy in units of Joules to units of kWh.

Once you have the amount of energy in kWh, you know that each kWh costs 60 cents. So you multiply:

<br /> (\mbox{energy in kWh}) \times \left(\frac{\$ 0.60 }{ \mbox{kWh}}\right)<br />

to find the total cost in dollars.
 

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