Should the friction force be negative?
Even if I changed the sign on any of the numbers, my answer would still be incorrect. If I change the sign on either forces, I would get a smaller number and therefore a smaller velocity as an answer.
I made an error, it should be 18003.75N
Maximum Frictional Force: ## 9.8 * 1500 * cos(15) = 14199.11 ##
Force due to gravity: ## 9.8 * 1500 * sin(15) = 3804.64 ##
Added together: ## 14199.11 + 3804.64 = 18003.75 N ##
## (m v^2) / r = 18003.75 ##
## (1500 v^2 / 70) = 18003.75##
## v = 29.0 m/s ##
Hmm, I still don't get the right answer. I tried adding the force of gravity in the direction of the incline to the frictional force (which would just double it), so I got:
## (m v^2) / r = 28398.22 ##
## (1500 v^2 / 70) = 28398.22 ##
## v = 36.4 ##
I figured that when the centripetal force exceeds the maximum frictional force, the car would skid. Solving for the maximum frictional force only requires the normal force, so I didn't include any other forces. Where would I have to use the friction force?
Homework Statement
A concrete highway curve of radius 70 m is banked at a 15° angle. What is the maximum speed with which a 1500 kg rubber tired car can take this curve without sliding? The static friction coefficient is 1.
Homework Equations
Centripetal Force = ## (m v^2) / r ##
Maximum...