Recent content by Jaehyun

But (CAB + CAB') = CA(B+B') = CA is missing the NOT portion (CAB + CAB')'. Edit: I was rushing the question so much and I finally realized what I was doing wrong thanks BvU for putting up with me it's 2am where I live and I'm clearly not in the right mind at the moment. Solved.

(A + C) (CAB + CAB')' (A + C) (CA)' (B + B')' (A + C) (C' + A') (B + B')' (AC' + AA' + CC' + CA') (B + B')' (AC' + CA') (B + B')' So then (B + B')' = 0 meaning there is no simplified expression?

I don't think this rule would work as it leads to a false (CA)' (B + B')' = (CA)' (1)' = 0 unless this does not work for NOT.

I'm confused on how this rule: (A+B)' = A'B' is used to help with (CAB + CAB')'.

Homework Statement (A OR C) AND NOT(C AND A AND B OR C AND A AND NOT B) or (A + C) (CAB + CAB')' Relevant Equations (A+B)' = A'B' A(B+C) = (AB) + (AC) (AB)' = A' + B' The attempt at a solution I'm not sure how I'm suppose to expand (CAB + CAB')' for simplifying. I keep arriving at false which...