Recent content by Jamadar

Thanks for all the help everyone.

So then the answer would be W/4?

So I got some more information if anyone still is helping. while the pole is falling, at any location of the pole there are forces that try to snap the pole. One goes up perpendicular to the pole and the other comes down perpendicular to the pole. That is why an old fragile pole breaks down...

So I also realized that intertia doesn't really take into account of center of mass and only applies to the whole rod (according to my tutor) so I is actually equal to mL^2/3. I redid the calculations and got 3W/4. My tutor also mentioned that F=N-mg which he changed into ma=N-ma (he changed...

Ok so I did find the correct I being I=mr^2/3 which I changed into I=m(L/2)^2/3 to take into account that I'm calculating it at the center of mass. I had fixed my A=T/I equation to make it into A=6W/(Lm). Then I plugged it into the F_{net}= ma_{com} equation where a is the tangential...

I can think of two forces after drawing it and one is the force of gravity acting upon it pushing it down and the other is the force of the support pushing it up. May I ask how finding the net force on the rod would help? I'm only looking for the force on support. I don't know the net force...

Still nothing.

My apologies for messing up a few times in what I said. I had put linear acceleration as AL/2 which I got under the circular motion section. http://en.wikipedia.org/wiki/Tangential_acceleration#Tangential_and_centripetal_acceleration I had then replaced the a from F=ma with linear acceleration...

Yes that was a typo, I have corrected it. The only forces that I can think of is the force of gravity on the pole and the force of the support acting on the pole. First I had L as the length of the pole. I then used I=mr^2 which became I=m(L/2)^2. I then got T=WL/2 from T=IA because gravity...

Homework Statement A thin uniform pole of length 30 m is pivoted at the bottom end. Calculate the most probable point of rupture on the pole as the pole falls.Homework Equations I'm really not sure how to start.The Attempt at a Solution None, our professor gave us this as a challenge problem...

Homework Statement A uniform thin rod of weight W is supported horizontally by two bricks at its ends. At t=0 one of these bricks is kicked out quickly. Calculate the force on the other support immediately thereafter - it should be in terms of W.Homework Equations T=IA F=ma W=mg I=mr^2/3...