Recent content by jamesdoinghwk

ok thanks got it now!

may bad, using internet calculators.. so I got T = 207.7 K

a. Total power entering atmosphere = (pi r^2)(solar constant) = 1.75 X 10^17 watts b. 31% would be absorbed my the Earth if there was no atmosphere, 5.4 X 10^16 watts absorbed. c. Earth absorbs 5.4 X 10^16/ 4pi r^2 = 105.5 watts/m^2 = (boltzmann's constant)T^4, Thus T = this will be in...

Ok, so pi r^2 for all equations, so working more in 2d then.. thanks alot!

so this is what i have now a. Total power entering atmosphere = (4pier^2)/2(solar constant) = 3.5 X 10^17 watts b. 31% would be absorbed my the Earth if there was no atmosphere, 1.09 X 10^17 watts absorbed. c. The temperature of Earth if 1.09 X 10^17 absorbed and rest is sent back to...

no wait that's wrong still, should be 3.5 times ten to the 17th. then take 31 % of that...

have = half

no.. am I suppose, ha yah i am! ok so make it X 10^12, and should I be dividing the 108.5 ten to the twelve by have the area of the Earth to get, 424.5 watts/ meter squared?

Well that's why i divided by 2, and albedo is the pecentage of energy the Earth absorbs...

My attempt is a. Total power entering atmosphere = (4pier^2)/2(solar constant) = 350 X 10^9 watts b. 31% would be absorbed my the Earth if there was no atmosphere, 108.5 watts absorbed. c. The temperature of Earth if 108.5 watts absorbed and rest is sent back to space would be i have no...

Assuming the EarthÕs radius is 6378 km, the solar constant is 1370 W/m2 and our planetary albedo is 0.31 then a) Determine the total power (from solar energy) entering the EarthÕs atmosphere b) What power would be absorbed by the EarthÕs surface in the absence of an atmosphere...