Hi Mark,
So the goal of this function is to accept the FFT of a discrete set of data points which represent an acceleration signal a(t) and find the position over time x(t).
The input is fft(a(t))=a(w).
I know that for ever harmonic in a(w), that the corresponding time domain signal is An(t) =...
Hello,
Thank you for taking time to read my post.
I have a discrete set of data points that represent an acceleration signal. I want to take the integral of this set of points twice so as to get a function which represents the position over time.
To accomplish this, I have taken the FFT of the...
Works perfectly! I can't believe that it was that straight forward. You have been very helpful. Here is my python code as a contribution to the community (this is obviously for a dummy signal):
import numpy as n
import matplotlib.pyplot as plt
from scipy.fftpack import fft, ifft, fftfreq...
Hello,
Thank you for taking time to read my post.
Background: I have a accelerometer project that I am playing with that gives me the acceleration of the object. I can plot this data and it looks very nice. I want to integrate this to get the velocity and then integrate it again to get the...
Hello,
I built a small potato cannon out of PVC pipe/steel. It's 15.5 cm long, and about 7.6 cm wide on the inside. It's made of 2 parts the barrel and combustion chamber (or as i refer to, "the death chamber"). the "death chamber" is cylinder about 7.6 cm long and 7.6 cm thick.
and the...
ok so tell me if i do this right
if i have a spring that has 1 lbs/in which equals 175.12 N/m
and if I put that into this equation.
(1/2)mv2 = (1/2)kx2
.5(.057)9.9^2=.5(175.12)x^2
then that x=.1786
which is roughly 7.03 inches.
Is this all correct?
what if i shaved my tennis balls (don't laugh) and lubed the pipe with a silicon based oil? (like they use for cleaning gun barrels, like waxing it) that would minimize friction wouldn't it?
and yes it is getting just a bit.
so pulling it back 12 inches gives a .285 lbs.
So if a spring says...
http://www.boltscience.com/pages/convert.htm
why is it when I try and input my work with this calculator (above)
I get a huge error (like 300 lbs/in)?
also would this be right then?
(1/2)mv2 = (1/2)kx2
.5(.057)9.9^2 = 25x^2
x=.3342
so I would only need to pull it back .334 of a meter with a...
ok 50 N/m = 442.53 lbs/in (and vice versa)
@cupid.callin
so with (1/2)mv2 = (1/2)kx2
and
mass=.057kg
V=9.9 m/s
k=50
I'd be write to do the equation and get
(1/2).057*9.9^2 = (1/2)50x^2
x=.334 Would this be accurate?
Thanks again (things are starting to get clearer)
ok the fact is I'm trying to build one of these at home and I want to find out what type of spring to buy.
and my math didn't make any sense when it said 247 pound/in spring so i was hoping to find the right answer with you guys.
But i guess to my dilemma no one can help me unless if I have...
So your saying 9.9 m/sec is wrong to begin with?
Just a reminder I'm a HS student and my teacher just got done teaching us basic 2-d kinematics and now is moving into springs and forces and half the equations that r being presented to me I never even seen before in my life.
"Physicists seldom...