Recent content by jase951

I'm understanding it now. Many Thanks again! :)

Thanks! So I6 + I2 = I1. I should be able to do the algebra from these. Could you tell me why you would have I6 there, because of the EMF? As I thought that that current through the EMF would be the same as I1 - or is it because the bottom node is split? Thanks again!

I would assume that the 6 currents would be that of where the resitors are. where would the 6th be? For the first loop on the left I have: 200V = 10.I1 (thus I1 = 10A). 2nd loop I have: 0V = 8.I2 + 10.I1 + 20.I3 + 20.I5 3rd: -125V = 30.I4 + 20.I5 For the nodes, and K's 1st Law: I3 + I4 = I5...

Thanks for the reply. I'm trying it again. I've updated the image. I have managed to have do this with 2 loops, but the the 3 loops. Using Kichoff's second law, I'll have 3 equations I understand. What I am confused about is where I need to lable the current changes to enable me to use...

Thanks for your help. I've got it now.

I had a feeling that was going to be the answer. One last question about 'E': is this the stiffness of the structure or is this a property of the material stiffness only? Thanks!

Hi I've started a mechanics module and just wanted to know, what is the difference between Young's Modulus ('e') and the E = Stress/Strain? Thanks! Jase

Thanks! So the middle section, we'd have 0V = (Ix20) + (Ix10) + (Ix8) + (Ix20)?

Homework Statement I what to know how I form an equation for the middle loop, as there is no EMF in that part. Or, how do I go about forming the equations? Also, am I right to say that I should have 3 equations? Homework Equations http://www.theground.co.uk/CCF18012009_00000.jpg...