Recent content by Jason000000

  1. J

    MHB Forecasting Automotive Sales: Choose the Best Approach for Accurate Results

    Hey Jameson .. thanks for the input .. i will pass you what I achieved to check it out .. thanx
  2. J

    MHB Forecasting Automotive Sales: Choose the Best Approach for Accurate Results

    my suggestion is to apply the "moving average" method of forecasting on company 1, and get the usual MAD, MSE & MAPE. and as for the 2nd company.. due to very limited records I suggest applying the "naive" method. And also get the MAD, MSE & MAPE. What do you think?
  3. J

    MHB Forecasting Automotive Sales: Choose the Best Approach for Accurate Results

    Hi Jameson, yes you are right it's a time series method .. one of many forecast technique ... and my guess it's the seasonality pattern of time series. The problem is how to apply this seasonal pattern on both companies! Year...1st company sales ( In millions) 2010.........22 2011.........11...
  4. J

    MHB What is the probability that the ball was labeled

    because I have extra to his answer:- P(F) x P(M) = 17/50 x 33/50 = 0.34 x 0.66 = 0.2244 P(F1|F2) = 17/50 x 16/49 = 0.34 x 0.326 = 0.111 is it correct to multiply and get these results?
  5. J

    MHB Forecasting Automotive Sales: Choose the Best Approach for Accurate Results

    Two automotive companies are trying to forecast the next year sales. They try to select the best approach and tool to make the forecast as accurate as possible. Compare between the different approaches of forecasting and advise by return the one you suggest, and mention why did not you use the...
  6. J

    MHB Ask a Forecasting Question | Get Answers Here

    kindly advise where can I ask a question about forecasting? can it be here? or elsewhere? .. thank you...
  7. J

    MHB What is the probability that the ball was labeled

    can u confirm above the answers I provided before your reply? many thanx!
  8. J

    MHB What is the probability that the ball was labeled

    I finally figured it out .. but I would appreciate if anyone can confirm the answers .. thanx for Q1. P(L|F) = 10/17 for Q2. P(F) x P(M) = 17/50 x 33/50 = 0.34 x 0.66 = 0.2244 for Q3. P(F1) = 17/50 & P(F2) = 16/49 P(F1|F2) = 17/50 x 16/49 = 0.34 x 0.326 = 0.111
  9. J

    MHB What is the probability that the ball was labeled

    A tank contains 50 balls. 10 are frosted (F) and labeled (L), 23 are mild (M) and unlabeled, 7 are frosted and not labelled (N), 10 are mild and labeled. 1. A ball is randomly selected from the tank and it was frosted. What is the probability that the ball was labeled? 2. The 1st ball was...
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